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kaheart [24]
3 years ago
6

Write the equation of a line parallel and perpendicular to the given line and passing through (1, -1), y=2/5x-3

Mathematics
1 answer:
andre [41]3 years ago
5 0

Answer:

Parallel: y = (2/5)x - 7/5

Perpendicular: y = (-5/2)x + 3/2

Step-by-step explanation:

Parallels lines have the same slope,

And it also needs to pass through (1, -1)

for an equation as y = mx + b, the only information missing is the y-intercept, it can be found replacing everything else.

-1 = (2/5)(1) + b

-1 - 2/5 = b

-7/5 = b

The equation for the line parallel is y = (2/5)x - 7/5

Perpendiculars when you multiply its slopes the result is -1 , assuming m = the slope of the perpendicular line

(2/5) * m = -1

m = -5/2

Now you have to replace the point and the slope to get the y-intercept as the previous line:

y = mx + b

-1 = (-5/2)(1) + b

-1 + 5/2 = b

3/2 = b

y = (-5/2)x + 3/2

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Read 2 more answers
If u(x)= x^5-x^4+x^2 and v(x)= -x^2, which expression is equivalent to (u/v)(x)? Ox^3-x^2 O -x^3+x^2 O-x^3+x^2-1 Ox^3-x^2+1​
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<u>Given</u>

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<u>(u/v)(x) = </u>

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