Answer:
x=3
Step-by-step explanation:
1st distribute
8x-6-8=4+2x
2nd add
8x-14=4+2x
3rd move like terms
8x-2x=4+14
4th add the numbers
6x=18
5th divide both sides by 6
6x/6=18/6
x=3
Answer:
B) x = 2, y = 3 and z = 5.
Step-by-step explanation:
3x −2y + 4z = 20 .....A
-x + 5y+ 12z = 73 .....B
x + 3y −2z = 1 ......C
Adding B and C:
8y + 10z = 74 .... E
Multiply equation B by -3:
-3x - 9y + 6z = -3
Add this equation to A:
-11y + 10z = 17
Subtract this equation fro E:
19y = 57
y = 3.
Substitute y = 3 in equation E:
8*3 + 10z = 74
10z = 50
z = 5.
Finally substitute y = 3 and z = 5 into equation C:
x + 3(3) - 2(5) = 1
x + 9 - 10 = 1
x = 1 + 1
x = 2.
1/7 and 3/14......common denominator is 14
2/14 = 3/14
cross multiply
(14)(3) = (14)(2)
42 = 28...not correct...no, this does not form a proportion
little tip ** proportions are nothing but equivalent fractions and 1/7 does not equal 3/14...now if it would have been 1/7 and 2/14...then it would have been a proportion
Answer:
second choice
Step-by-step explanation:
The given sums ∑ have j = 1, j = 2, j = 3, j = 4, j = 5
Consider first j = 1 and substitute in the answers to see if we get the first term of the series -3
✅
2·1 - 5 = 2-5 = -3 ✅
3·1 - 6 = 3-6 = -3 ✅
❌
We see that last choice gives us as first term to be 1 not -3 so eliminate that possibility.
Consider now j = 2 and substitute in the answers to see if we get the second term of the series -1
✅
2·2 - 5 = 4-5 = -1 ✅
3·2 - 6 = 6-6 = 0 ❌
We see that third choice gives us as second term to be 0 not -1 so eliminate that possibility.
Consider now j = 3 and substitute in the answers to see if we get the third term of the series 1
❌
2·3 - 5 = 6-5 = 1 ✅
We see that first choice gives us as third term to be -1/3 not 1 so eliminate that possibility.
Now we are left with the second choice as the only possibility.