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4 years ago

Define enlargement and reduction.

1 answer:

3 0

An enlargement is a type of dilation where the absolute value of the scale factor is greater than 1. A reduction is a type of dilation where the absolute value of the scale factor is between 0 and 1.

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Find the value of sec(theta°)cos(theta°) for the following values of theta. <br> b. theta = 225

Nesterboy [21]

Answer:

sec(theta°)cos(theta°) = 1

Step-by-step explanation:

given data

(theta°) = 225

to find out

sec(theta°)cos(theta°)

solution

as we know that given equation

(theta°) = 225

cos(theta°) will be

cos(225°) = -0.7071 .................................1

so we know

sec(theta°) = $\frac{1}{cos(theta)}$ ..............2

so put here value of cos(theta°)

sec(theta°) = $\frac{1}{-0.7071}$

sec(theta°) = - 1.4142

sec(theta°)cos(theta°) = -0.7071 × ( - 1.4142 )

sec(theta°)cos(theta°) = 1

so answer is sec(theta°)cos(theta°) = 1

8 0

4 years ago

StartFraction one-half left-parenthesis x plus 12 right-parenthesis equals 4 x minus 1.(x + 12) = 4x – 1

Alika [10]

Answer:

1/2.(x+12)=4x-1

x+12=2(4x-1)

x+12=8x-2

Group like terms

12+2=8x-x

14=7x

Divide both sides by 7

x=2

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

There are 250 wolves in a national park. the wolf population is increasing at a rate of 16% per year. write an exponential model

Helga [31]

$\qquad \textit{Amount for Exponential Growth} \\\\ A=P(1 + r)^t\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &250\\ r=rate\to 16\%\to \frac{16}{100}\dotfill &0.16\\ t=\textit{elapsed time} \end{cases} \\\\\\ A=250(1 + 0.16)^{t}\implies A=250(1.16)^t \\\\[-0.35em] ~\dotfill$

$A=P(1 + r)^t\qquad \begin{cases} A=\textit{accumulated amount}\dotfill &1000\\ P=\textit{initial amount}\dotfill &250\\ r=rate\to 16\%\to \frac{16}{100}\dotfill &0.16\\ t=\textit{elapsed time} \end{cases} \\\\\\ 1000=250(1.16)^t\implies \cfrac{1000}{250}=1.16^t\implies 4=1.16^t \\\\\\ \log(4)=\log(1.16^t)\implies \log(4)=t\log(1.16) \\\\\\ \cfrac{\log(4)}{\log(1.16)}=t\implies \stackrel{\textit{about 9 years and 4 months}}{9.34\approx t}$

7 0

2 years ago

How do you write 19% as a fraction in simplest form?

zmey [24]

19% is 19/100 and there is nothing that can go into these numbers evenly so this is the simplest form

5 0

4 years ago

Read 2 more answers

Solve for x 9(x-1) = 2

Katen [24]

Answer: x = 9/11

Step-by-step explanation:

First, distribute 9 to x and -1

9x - 9 = 2

Then add 9 to both sides

9x = 11

Then divide both sides by 9

x = 9/11

Hope it helps :)

4 0

3 years ago