Did you really think someone would write you a whole essay just for fun
Answer:
I guess. Just post question.
F=\dfrac{9}{5}C+32\\\\A.\\\dfrac{9}{5}C+32=F\ \ \ |-32\\\\\dfrac{9}{5}C=F-32\ \ \ |\cdot\dfrac{5}{9}\\\\C=\dfrac{5}{9}(F-32)
B.\\F=212\to C=\dfrac{5}{9}(212-32)=\dfrac{5}{9}\cdot180=100\\\\212^oF=100^oC
C.\\F=80\to C=\dfrac{5}{9}(80-32)=\dfrac{5}{9}\cdot48\approx26.7\\\\80^oF\approx26.7^oC
Answer:
sin A = 15/17
sec A = 17/8
Step-by-step explanation:
15 cot A = 8
First get cot A alone.
cot A = 8 / 15
Since cot is the reciprocal of tan then flip 15 and 8.
tan A = 15 / 8
Now you have the opposite and adjacent sides, just find the hypotenuse with Pythagorean's theorem
15^2 + 8^2 = 289
= 17
Now that you have all the sides use the opposite and hypotenuse to get sine and the adjacent and hypotenuse to get cosine then flip to get secant.
sin A = 15/17
cos A = 8/17
sec A = 17/8