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Misha Larkins [42]
3 years ago
11

If the length of AC equals 18, what is the length of the midsection DE

Mathematics
1 answer:
Free_Kalibri [48]3 years ago
7 0

Answer:

The length of the midsegment is 9 ⇒ (B)

Step-by-step explanation:

In a triangle,

  • The midsegment is the segment which joining the midpoints of two opposite sides of it
  • The length of the midsegment is half the length of the third side in the triangle which opposite to it

<em>Let us use this rule to solve our question</em>

In Δ AC

∵ DE is the midsegment of it

∵ DE is opposite to the side AC

∴ The length of DE = 1/2 the length of AC

∵ The length of AC = 18

∴ The length of DE = 1/2 × 18

∴ The length of DE = 9

∴ The length of the midsegment is 9

The correct answer is B

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Answer:

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a) The width of the confidence interval becomes wider as the confidence level increases.

The above statement is true as the confidence level increases the width increases as the absolute value of test statistic increases.

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What is the distributive property for 9−12x+6y=
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Answer:

Step-by-step explanation:

Give the rate of change of sales revenue of a store modeled by the equation S'(t)= -30t^{2} + 420t. The Total sales revenue function S(t) can be gotten by integrating the function given as shown;

\int\limits {S'(t)} \, dt = \int\limits ({-30t^{2}+420t }) \, dt \\S(t) = \frac{-30t^{3} }{3}+\frac{420t^{2} }{2}\\  S(t)= -10t^{3} +210t^{2} \\

a) The total sales for the first week after the campaign ends (t = 0 to t = 7) is expressed as shown;

Given\ S(t) = -10t^{3} + 210t^{2}

S(0) = -10(0)^{3} + 210(0)^{2}\\S(0) = 0\\S(7) = -10(7)^{3} + 210(7)^{2}\\S(7) = -3430+10,290\\S(7) = 6,860

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= 6,860 - 0

Total sales for the first week = $6,860

b) The total sales for the secondweek after the campaign ends (t = 7 to t = 14) is expressed as shown;

Total sales for the second week = S(14)-S(7)

Given S(7) = 6,860

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The total sales for the second week after campaign ends = 13,720 - 6,860

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