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Misha Larkins [42]
3 years ago
11

If the length of AC equals 18, what is the length of the midsection DE

Mathematics
1 answer:
Free_Kalibri [48]3 years ago
7 0

Answer:

The length of the midsegment is 9 ⇒ (B)

Step-by-step explanation:

In a triangle,

  • The midsegment is the segment which joining the midpoints of two opposite sides of it
  • The length of the midsegment is half the length of the third side in the triangle which opposite to it

<em>Let us use this rule to solve our question</em>

In Δ AC

∵ DE is the midsegment of it

∵ DE is opposite to the side AC

∴ The length of DE = 1/2 the length of AC

∵ The length of AC = 18

∴ The length of DE = 1/2 × 18

∴ The length of DE = 9

∴ The length of the midsegment is 9

The correct answer is B

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BigorU [14]
Well we want to pull out the important values here to determine our expression which in this case is $2 and $.50. Since the fixed cost is 2 and there is .50 per kilometer. We can say that .50(m)+2 is our expression. Hope this helps! I apologize if you were looking for something else in advance.
5 0
3 years ago
Read 2 more answers
A physicist examines 25 water samples for nitrate concentration. The mean nitrate concentration for the sample data is 0.165 cc/
xz_007 [3.2K]

Answer:

The 80% confidence interval for the the population mean nitrate concentration is (0.144, 0.186).

Critical value t=1.318

Step-by-step explanation:

We have to calculate a 80% confidence interval for the mean.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

The sample mean is M=0.165.

The sample size is N=25.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

s_M=\dfrac{s}{\sqrt{N}}=\dfrac{0.078}{\sqrt{25}}=\dfrac{0.078}{5}=0.016

The degrees of freedom for this sample size are:

df=n-1=25-1=24

The t-value for a 80% confidence interval and 24 degrees of freedom is t=1.318.

The margin of error (MOE) can be calculated as:

MOE=t\cdot s_M=1.318 \cdot 0.016=0.021

Then, the lower and upper bounds of the confidence interval are:

LL=M-t \cdot s_M = 0.165-0.021=0.144\\\\UL=M+t \cdot s_M = 0.165+0.021=0.186

The 80% confidence interval for the population mean nitrate concentration is (0.144, 0.186).

6 0
3 years ago
Answer the question below
lys-0071 [83]

Answer:

A) -1

Step-by-step explanation:

\frac{3 + 2\sqrt{5} }{2\sqrt{5}-3 } \\

We can rewrite 2√5 - 3 as -(3 + 2√5)

Therefore,

\frac{3+ 2\sqrt{5} }{-(3 + 2\sqrt{5} )} \\

We can cancel out 3 + 2√5 both in the numerator and the denominator. So we get

= 1/-1

= -1

Answer : A) -1

Thank you.

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3 years ago
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Natali5045456 [20]
Good morning from Canada!

What we know:
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So, we are looking for how many quires can fit into a ream. All we have to do is divide the number of sheets in a ream (100) by the number of sheets in a quire (25) because dividing allows us to see how many times a specific number can go into another number, which is what we are looking for. (How many quires are in a ream).

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belka [17]

Answer:

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Step-by-step explanation:

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