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chubhunter [2.5K]
3 years ago
12

What is 500 dollars at 4% for 3 years

Mathematics
1 answer:
worty [1.4K]3 years ago
7 0
500 +  (\frac{100 + 4}{100})^{3} = $<span>562.432.
</span>
original amount + ((100 + percentage) / 100)^number of years
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anyanavicka [17]
Make another one with a picture please
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2 years ago
2(w-1)+8=6(2w-4) please help w=?
sergejj [24]

Answer:

W = 3

Step-by-step explanation:

2(W - 1) + 8 = 6(2w - 4)

2w - 2 + 8 = 12w - 24

2w + 6 = 12w - 24

6 = 10w - 24

30 = 10w

3 = W

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5 0
3 years ago
(02.01)Line segment CD has a length of 3 units. It is translated 2 units to the right on a coordinate plane to obtain line segme
kipiarov [429]
The translation of a segment or object, from one location to another on the plane, doesn't change its length, just its location.

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7 0
3 years ago
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Find an equivalent function for the following: <br><br> f(x) = 3(2)4x
n200080 [17]
Hi there!

To find an equivalent function for this function, we can just simplify it. 

f(x) = (6)4x

f(x) = 24x
is an equivalent function. 

Hope this helps!
8 0
3 years ago
Solve each inequality, and then drag the correct solution graph to the inequality.
Nesterboy [21]

The correct solution graph to the inequalities are

4(9x-18)>3(8x+12)  →  C

-\frac{1}{3}(12x+6) \geq -2x +14  → A

1.6(x+8)\geq 38.4  →  B

(NOTE: The graphs are labelled A, B and C from left to right)

For the first inequality,

4(9x-18)>3(8x+12)

First, clear the brackets,

36x-72>24x+36

Then, collect like terms

36x-24x>36+72\\12x >108

Now divide both sides by 12

\frac{12x}{12} > \frac{108}{12}

∴ x > 9

For the second inequality

-\frac{1}{3}(12x+6) \geq -2x +14

First, clear the fraction by multiplying both sides by 3

3 \times[-\frac{1}{3}(12x+6)] \geq3 \times( -2x +14)

-1(12x+6) \geq -6x +42

Now, open the bracket

-12x-6 \geq -6x +42

Collect like terms

-6 -42\geq -6x +12x

-48\geq 6x

Divide both sides by 6

\frac{-48}{6} \geq \frac{6x}{6}

-8\geq x

∴ x\leq  -8

For the third inequality,

1.6(x+8)\geq 38.4

First, clear the brackets

1.6x + 12.8\geq 38.4

Collect likes terms

1.6x \geq 38.4-12.8

1.6x \geq 25.6

Divide both sides by 1.6

\frac{1.6x}{1.6}\geq  \frac{25.6}{1.6}

∴ x \geq  16

Let the graphs be A, B and C from left to right

The first graph (A) shows x\leq  -8 and this matches the 2nd inequality

The second graph (B) shows x \geq  16 and this matches the 3rd inequality

The third graph (C) shows x > 9 and this matches the 1st inequality

Hence, the correct solution graph to the inequalities are

4(9x-18)>3(8x+12)  →  C

-\frac{1}{3}(12x+6) \geq -2x +14  → A

1.6(x+8)\geq 38.4  →  B

Learn more here: brainly.com/question/17448505

8 0
2 years ago
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