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Nadusha1986 [10]
3 years ago
15

The triangles are isosceles and ΔABC : ΔJKL. What is the length of pie?A=2.5cmC=4cmk=5cm

Mathematics
1 answer:
Pavlova-9 [17]3 years ago
6 0
The length of the pie is 20cm2
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Need help with solving and understanding
prohojiy [21]
Let start off with 5/8+7/8= 1 4/8
Now it's 13+1 4/8= 14 4/8 or 14 1/2 :)
5 0
3 years ago
Can you please show the working?
creativ13 [48]

The Price of Car A rounded to the Nearest £100 is £12400

The Price of Car B rounded to the Nearest £100 is £16800

The Price of Car C rounded to the Nearest £100 is £14600

Difference between the Rounded Price and Original Price of Car A :

⇒ (£12400 - £12380) = £20

Difference between the Rounded Price and Original Price of Car B :

⇒ (£16800 - £16760) = £40

Difference between the Rounded Price and Original Price of Car C :

⇒ (£14600 - £14580) = £20

From the above, We can Notice that :

The Price of Car B changes by the greatest amount.

4 0
3 years ago
Find the value of x<br> A.25<br> B.85<br> C.75<br> D.105
Masteriza [31]

Answer:

The value of x is 75

Step-by-step explanation:

First we need to find the other angle that doesn't have a number in it.

To find the degrees of the other angle we subtract 155 from 180.

180 - 155 = 25

Now we have to find the value of x. Add 80 and 25 together to get 105. A triangle is going to be 180 degrees. Subtract 105 from 180.

180 - 105 = 75

Now we will add 80, 25, and 75 to check our work.

80+25+75 = 180

7 0
3 years ago
Solve 3x2+7x+1=0 using the quadratic formula.
NNADVOKAT [17]

Answer:

x=\frac{-7+-\sqrt{37} }{6}

Step-by-step explanation:

This (±) goes between the -7 and \sqrt{37}

3x^{2} +7x+1=0

ax^{2} +bx+c

-b ± \sqrt{b^2-4ac}/2a

-7 ± \sqrt{(7)^2-4(3)(1)}/2(3)

-7 ± \sqrt{49-12}/6

-7 ± \sqrt{37}/6

7 0
3 years ago
Evaluate the sine of angle X for the right triangle below.
bezimeni [28]

Answer:

\frac{7}{25}

Step-by-step explanation:

sinx = \frac{opposite}{hypotenuse}

The hypotenuse = 25 since 7, 24, 25 ← Pythagorean triple

Hence

sinx = \frac{7}{25}

6 0
3 years ago
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