Z+11≤17<br> What is the answer?

Find the area of the shaded region.

Papessa [141]

Answer:

21.46 cm²

Step-by-step explanation:

because the question want only for the SHADED REGION but NOT AREA OF THE SQUARE

(if we just multiply 10x10. you will get the area of a square which is hundered)

To find the shaded region:

1. area of a circle is πr² (we have 4 circle there)

2. Find the area of all circle

# how do we know the radius?

- half of 10 is 5

- 5 is the diameter of each circle

- the radius is half of 5 which is 2.5

- π(2.5)² = 25/4π (area of 1 circle)

3. since we have 4 circle then, 25/4π x 4 = 25π

4. the area of the square is 100cm²

5. we want the shaded region so we have to minus the area of the circle

6. 100 - 25π (use your calculator to find the answer)

answer should be 21.46 cm²

(hope this helps)

8 0

4 years ago

Which of the binomials below is a factor of this trinomial?

8_murik_8 [283]

Answer:

C. x - 4

Step-by-step explanation:

The best way to do this is to first take out GCF

6(x² - x - 12)

Then we factor

6(x - 4)(x + 3)

We can now see our answer.

8 0

3 years ago

Read 2 more answers

3. For the polynomial: ()=−2(+19)3(−14)(+3)2, do the following:A. Create a table of values that have the x-intercepts of p(x) in

Pepsi [2]

Part A. We are given the following polynomial:

$\mleft(\mright)=-2\mleft(+19\mright)^3\mleft(-14\mright)\mleft(+3\mright)^2$

This is a polynomial of the form:

$p=k(x-a)^b(x-c)^d\ldots(x-e)^f$

The x-intercepts are the numbers that make the polynomial zero, that is:

$\begin{gathered} p=0 \\ (x-a)^b(x-c)^d\ldots(x-e)^f=0 \end{gathered}$

The values of x are then found by setting each factor to zero:

$\begin{gathered} (x-a)=0 \\ (x-c)=0 \\ \text{.} \\ \text{.} \\ (x-e)=0 \end{gathered}$

Therefore, this values are:

$\begin{gathered} x=a \\ x=c \\ \text{.} \\ \text{.} \\ x=e \end{gathered}$

In this case, the x-intercepts are:

$\begin{gathered} x=-19 \\ x=14 \\ x=-3 \end{gathered}$

The multiplicity are the exponents of the factor where we got the x-intercept, therefore, the multiplicities are:

Part B. The degree of a polynomial is the sum of its multiplicities, therefore, the degree in this case is:

$\begin{gathered} n=3+1+2 \\ n=6 \end{gathered}$

To determine the end behavior of the polynomial we need to know the sign of the leading coefficient that is, the sign of the coefficient of the term with the highest power. In this case, the leading coefficient is -2, since the degree of the polynomial is an even number this means that both ends are down. If the leading coefficient were a positive number then both ends would go up. In the case that the leading coefficient was positive and the degree and odd number then the left end would be down and the right end would be up, and if the leading coefficient were a negative number and the degree an odd number then the left end would be up and the right end would be down.

Part C. A sketch of the graph is the following:

If the multiplicity is an odd number the graph will cross the x-axis at that x-intercept and if the multiplicity is an even number it will tangent to the x-axis at that x-intercept.