1) factor the denominators: 2b/(b-1)2 - 2/ (b-1)2
2) MAKE SURE YOU HAVE A COMMON DENOMINATOR
3) combine the numerators: 2b-2/(b-1)2
4) distribute 2 from numerator: 2(b-1)/(b-1)2
5) simplify; answer is 2/(b-1)
Answer:
14,535
Step-by-step explanation:
765 times 95 : 765 x 95 = 72,675
divided by 5 : 
Let me know if you want an even more in-depth answer
Happy to do so !
<span>2 significant digits.
Let's see what the range of possible values you can have for 1.3540980 if your uncertainty is +/- 2%
2% of 1.3540980 = 0.02 * 1.3540980 = 0.027082
So the lowest possible value for your result is
1.3540980 - 0.027082 = 1.327016
The largest possible result is
1.3540980 + 0.027082 = 1.38117996
Notice that only the 1st 2 digits of the result match which is reasonable since a 2% error means that your result is only accurate to within 1 part in 50.</span>
Answer:
Anything in the form x = pi+k*pi, for any integer k
These are not removable discontinuities.
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Explanation:
Recall that tan(x) = sin(x)/cos(x).
The discontinuities occur whenever cos(x) is equal to zero.
Solving cos(x) = 0 will yield the locations when we have discontinuities.
This all applies to tan(x), but we want to work with tan(x/2) instead.
Simply replace x with x/2 and solve for x like so
cos(x/2) = 0
x/2 = arccos(0)
x/2 = (pi/2) + 2pi*k or x/2 = (-pi/2) + 2pi*k
x = pi + 4pi*k or x = -pi + 4pi*k
Where k is any integer.
If we make a table of some example k values, then we'll find that we could get the following outputs:
- x = -3pi
- x = -pi
- x = pi
- x = 3pi
- x = 5pi
and so on. These are the odd multiples of pi.
So we can effectively condense those x equations into the single equation x = pi+k*pi
That equation is the same as x = (k+1)pi
The graph is below. It shows we have jump discontinuities. These are <u>not</u> removable discontinuities (since we're not removing a single point).