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3 years ago

-6+14 =12-8x what is x

Mathematics

1 answer:

navik [9.2K]3 years ago

5 0

8=12-8x
-4=8x
-4÷8=8x÷8
-0.5=x

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a certain number is both a perfect square and a perfect cube. Will it's square root and its cube root will always be different n

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Bumek [7]

Answer:

$x=-\frac{3}{2}, x=\frac{3}{2}$

Step-by-step explanation:

(1) To solve by factoring,

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Subtract 9 from both sides of the equation.

$\begin{aligned}&4 x^{2}-9=9-9\\&4 x^{2}-9=0\\&(2 x)^{2}-3^{2}=0\\&(2 x-3)(2 x+3)=0\end{aligned}$

Using zero factor principle, $2 x-3=0,2 x+3=0$

The solutions are $x=-\frac{3}{2}, x=\frac{3}{2}$ .

(2) To solve by complete the square ,

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Divide both sides of the equation by 4.

$\frac{4 x^{2}}{4}=\frac{9}{4}$

$\Rightarrow x^{2}=\frac{9}{4}$

Square root on both sides.

$\Rightarrow x=\pm \frac{3}{2}$

$x=-\frac{3}{2}, x=\frac{3}{2}$

(3) To solve by quadratic formula,

$4 x^{2}-9=0$

Here, a = 4, b = 0, c = –9

Quadratic formula, $x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

$x=\frac{-0 \pm \sqrt{0^{2}-4 \times 4 \times(-9)}}{2 \times 4}$

$\begin{aligned}&\Rightarrow x=\frac{\pm \sqrt{144}}{8}\\&\Rightarrow x=\pm \frac{3}{2}\\&\Rightarrow x=\frac{3}{2}, x=-\frac{3}{2}\end{aligned}$

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3 years ago