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2 years ago

PLSSS HELPPP WILL GIVE BRAINIEST TO WHO GIVES THE CORRECT ANSWER Which table shows a proportional relationship between x and y?

Mathematics

1 answer:

natka813 [3]2 years ago

8 0

Answer:

The third one

Step-by-step explanation:

Have a great day

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Can someone help me with this

pentagon [3]

Answer:

sas

Step-by-step explanation:

5 0

3 years ago

AB bisects CD at point M, CD bisects AB at point M, and AB = 4 x CM. Describe the relationship between AM and CD

padilas [110]

$\text{Given that AB bisects the line segment CD at the point M,}\\
\text{And CD bisects the line segment AB at the point M. so M is the }\\
\text{midpoint of both the line segements AB and CD.}\\
\\
\text{also we have given a relation that, }AB=4\times CM\\
\text{and we need to find a relation between AM and CD.}\\
\\
\text{observe that since M is the midpoint of CD, so we have }CD=2\times CM\\
\\
\Rightarrow CM=\frac{CD}{2}$

$\text{and M is midpoint of AB, so }AB=2\times AM\\
\\
\text{so with these substitutions, the given realtion gives}\\
\\
AB=4\times CM\\
\\
\Rightarrow 2\times AM=4\times \frac{CD}{2}\\
\\
\Rightarrow 2\times AM=2\times CD\\
\\
\Rightarrow AM=CD$

Hence the relationship between AM and CD is : AM=CD

4 0

3 years ago

Help me please..!!!!

wariber [46]

I think it is D but i am not too sure

3 0

3 years ago

What is the value of a equation of a in the equation 5a - 10b = 45 when b = 3

inysia [295]

15.

You'd get this by multiplying the -10 by 3 then adding it to both sides. Then divide by 5.

3 0

3 years ago

Read 2 more answers

How many L of A 90% saline solution must be mixed with 4 L of a 50% saline solution to make a 74% solution ?

insens350 [35]

Answer:

6 L

Step-by-step explanation:

Given two solutions:

1st solution is 90% saline solution. Let the volume of this solution be $x$ litres.

2nd solution is 50% saline solution. Volume of this solution = 4 L

Resultant solution is 74% saline.

To find:

The volume of 1st solution = ?

Solution:

Total volume of the 74% saline mixture = (4+ $x$ ) Litres

We can write equation here, as per the percentage of saline in the mixtures.

90% of $x$ L + 50% of 4 L = 74% of ( $x$ +4)

$\Rightarrow \dfrac{90x}{100} + \dfrac{50}{100}\times 4 = \dfrac{74}{100}\times (x+4)\\\Rightarrow 90x + 200 = 74x+296\\\Rightarrow 90x-74x = 296-200\\\Rightarrow 16x = 96\\\Rightarrow x = \bold{6\ L}$

Therefore, the volume must be <em>6 L</em>.

8 0

3 years ago