1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
FromTheMoon [43]
3 years ago
9

Please help me with the Math. Thx in advance! Number's 8-11. THANK YOU!

Mathematics
2 answers:
Stella [2.4K]3 years ago
8 0
8 :=7
9= 2/3
10=3/20
11=4
koban [17]3 years ago
5 0
8. 7
9. 2/3
10. 3/20
11. 4
You might be interested in
(0.04)^3/2. .......<br>........<br><br>​
zhannawk [14.2K]

Answer:

Step-by-step explanation:

hello :

(0.04)^3/2=√(0.04)^3 =√(2²/10^2)^3 = √((2/10)^2)^3

(0.04)^3/2=√((2/10)^3)^2=8/1000 = 0.008

4 0
3 years ago
15 pts. Prove that the function f from R to (0, oo) is bijective if - f(x)=x2 if r- Hint: each piece of the function helps to "c
solniwko [45]

Answer with explanation:

Given the function f from R  to (0,\infty)

f: R\rightarrow(0,\infty)

-f(x)=x^2

To prove that  the function is objective from R to  (0,\infty)

Proof:

f:(0,\infty )\rightarrow(0,\infty)

When we prove the function is bijective then we proves that function is one-one and onto.

First we prove that function is one-one

Let f(x_1)=f(x_2)

(x_1)^2=(x_2)^2

Cancel power on both side then we get

x_1=x_2

Hence, the function is one-one on domain [tex[(0,\infty)[/tex].

Now , we prove that function is onto function.

Let - f(x)=y

Then we get y=x^2

x=\sqrt y

The value of y is taken from (0,\infty)

Therefore, we can find pre image  for every value of y.

Hence, the function is onto function on domain (0,\infty)

Therefore, the given f:R\rightarrow(0.\infty) is bijective function on (0,\infty) not on  whole domain  R .

Hence, proved.

3 0
3 years ago
A solution to a system of equations is at the point of intersection.
solniwko [45]

Answer:

true

Step-by-step explanation:

i dont have an explanation its just true

7 0
3 years ago
Which classification describes the system of linear equations?
Aleksandr [31]

Answer:

A system of two linear equations can have one solution, an infinite number of solutions, or no solution. Systems of equations can be classified by the number of solutions. If a system has at least one solution, it is said to be consistent . If a consistent system has exactly one solution, it is independent .

Step-by-step explanation:

3 0
1 year ago
Jane brought x shirts for $20 each and y skirts for $25 each she spent $210 in all. which equation represents this situation 2
miv72 [106K]

Answer:

Part A

20x + 25y = 210 --> D.

Part B

If jane purchased exactly 4 shirts she must have purchased Exactly ___ skirts. (round to the nearest tenth)

20*4 + 25y = 210 --> y = 5.2

is it possible for jane to purchase exactly 4 shirts? ____(yes or no)

no, because she can't buy 5.2 skirts.

5 0
4 years ago
Read 2 more answers
Other questions:
  • Hey please answer asap!
    10·2 answers
  • Themba has 6.75 cups of yoguri and needs to make 5 bowls of fruit dip. Each bowl
    11·1 answer
  • What is the range of 19, 12, 13, 3, 0, 0, 0, 0, 0, 0, 2, 13
    7·2 answers
  • Solve. Check for extraneous solutions.<br><br> (x-2)^(1/2) - (28 - 2x)^(1/4) = 0
    13·1 answer
  • Brainliest are involved lol
    15·2 answers
  • Gffffffffffffffffffffffffffffffffffffffffffffffffffffff,,,,
    8·1 answer
  • In a board game, you must roll two 6-sided number cubes. You can only start the game if you roll a 3 on at least one of the numb
    13·2 answers
  • un carro que se mueve con velocidad constante recorre 120 km en 75 minutos,¿en que tiempo recorrera el carro una distancia de 20
    9·1 answer
  • Jack has 2 3/4 ups of meat to fill for patties. If he uses 3/16 cups of meat for each patty, how many whole patties can jack mak
    12·1 answer
  • Three varieties of coffee Coffee​ A, Coffee​ B, and Coffee C are combined and​ roasted, yielding a 55​-lb batch of coffee beans.
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!