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mafiozo [28]
4 years ago
6

Please help! I'm very confused. 20 points.

Mathematics
1 answer:
malfutka [58]4 years ago
8 0
1) Use the distributive property to eliminate parentheses.
.. 3(6x) -3(5) -7(3x) -7(10) = 0
.. 18x -15 -21x -70 = 0 . . . . . . finish multiplying terms
.. -3x -85 = 0 . . . . . . . . . . . . . collect like terms
.. -85 = 3x . . . . . . . . . . . . . . . .add 3x
.. -85/3 = x . . . . . . . . . . . . . . .divide by 3
.. -28 1/3 = x . . . . . . . . . . . . . write as mixed number


2) 5 -(6 +9x) = 9 -(4x -1)
.. 5 -6 -9x = 9 -4x +1 . . . . . eliminate parentheses using the distributive property
.. -1 -9x = 10 -4x . . . . . . . . . collect like terms
.. -1 = 10 +5x . . . . . . . . . . . . add 9x
.. -11 = 5x . . . . . . . . . . . . . . . subtract 10
.. -11/5 = x . . . . . . . . . . . . . . divide by 5
.. -2 1/5 = x . . . . . . . . . . . . . write as mixed number
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A nation has five types of coins: sinds, dalts, lorgs, harps, and plunks.
USPshnik [31]
<h3>Answer:  d) plunk</h3>

=================================================

Work Shown:

When comparing units like inches, feet and yards, we need to get everything in the same unit to make a valid comparison. So we'd need to convert everything to inches for instance. The same idea applies to these five coins. We need to get everything in either lorgs, sinds, plunks, harps or dalts (pick one of those five).

It's effectively the same as trying to convert dollars into cents (eg: $1.37 converts to 137 cents). Or you can think of it as 1 dollar = 100 cents, 1 quarter = 25 cents, 1 dime = 10 cents, and so on.

The steps in the various sections below will aim to get all the coins converted to lorgs as our base unit. I found the lorg coin to be the smallest of value through trial and error, which is why I'm aiming to get everything in terms of lorgs.

The four given equations are

  • 1 sind = 4 lorgs
  • 2 plunks = 5 dalts
  • 5 sinds = 2 harps
  • 1 plunk = 3 harps

I'll refer to them as equation (1) through equation (4) in that order above.

--------------

1 sind = 4 logs .... equation (1)

5 sinds = 20 lorgs .... multiply both sides by 5

2 harps = 20 lorgs .... replace "5 sinds" with "2 harps" from equation (3)

1 harp = 10 lorgs .... divide both sides by 2; call this equation (5)

--------------

1 plunk = 3 harps .... equation (4)

1 plunk = 3*(1 harp)

1 plunk = 3*(10 lorgs) .... plug in equation (5)

1 plunk = 30 lorgs .... call this equation (6)

---------------

2 plunks = 5 dalts ..... equation (2)

5 dalts = 2 plunks

5 dalts = 2*(1 plunk)

5 dalts = 2*(30 lorgs) .... replace 1 plunk with 30 lorgs; see equation (6)

5 dalts = 60 lorgs

1 dalt = 12 lorgs ..... divide both sides by 5; call this equation (7)

----------------

We found the following conversions:

  • 1 sind = 4 lorgs .... given as equation (1)
  • 1 dalt = 12 lorgs .... found earlier as equation (7)
  • 1 harp = 10 lorgs .... equation (5)
  • 1 plunk = 30 lorgs  .... equation (6)

Each of those equations helps us see how much the value of the coins sind, dalt, harp, plunk are in terms of lorgs.

We can see that 1 plunk yields the most lorgs at 30. So the plunk coin is the most valuable. The lorg coin is least value since you need 4 of those coins to make the second lowest coin of 1 sind.

The order of the coins value from least to greatest is: lorg, sind, harp, dalt, plunk.

5 0
3 years ago
How do u solve <br> 131 + 16x = -331 + 5x
Veronika [31]
The goal of this equation is to solve for x. So, we can start by combining like terms.
(16x) and (5x) are like terms, so we would subtract (5x) over to the other side.

131 + 16x -5x = -331 + 5x - 5x
131 + 11x = -331

Then, we can combine the other like terms, which would be (131) and (-331). Subtract 131 on both sides.

131 - 131 + 11x = -331 - 131
11x = -462

Now, we need to divide the number before x, or the coefficient.

11x/11 = -462/11
x = -42

8 0
3 years ago
Read 2 more answers
Need help, I cant simplify this
Kisachek [45]

Answer:

7^{\frac{2}{5}}

Step-by-step explanation:

Step 1: First apply radical rule in the given expression.

\sqrt[n]{a}=a^{\frac{1}{n}}

Here, \sqrt[3]{7}=7^{\frac{1}{3}}, \sqrt[5]{7}=7^{\frac{1}{5}}

The expression becomes \frac{\sqrt[3]{7}}{\sqrt[5]{7}}=\frac{7^{\frac{1}{3}}}{7^{\frac{1}{5}}}  

Step 2: Now, apply exponent rule in the above expression

\frac{x^{m}}{x^{n}}=x^{m-n}  

So, the expression becomes, 7^{\left(\frac{1}{3}-\frac{1}{5}\right)}.

Step 3: Take cross multiply the denominator and numerator of the fraction in the power of 7.

\Rightarrow 7^{\left(\frac{1}{3}-\frac{1}{5}\right)}=7^{\left(\frac{5-3}{15}\right)}=7^{\frac{2}{5}}

The answer is 7^{\frac{2}{5}}.

Hence the simplified form of \frac{\sqrt[3]{7}}{\sqrt[5]{7}}=7^{\frac{2}{5}}.

3 0
3 years ago
Can someone please help me solve my IXL problems???????
WITCHER [35]
What is that "IXL" }:
6 0
3 years ago
Read 2 more answers
A cyclist rides 225 m each minute.About how long does it take to ride 15km? Show all fo your work
Elan Coil [88]
Speed = 225 metres per minute

Distance = 15 km = 15,000 metres

---------------------------------------------------

s=d/t

ts=d

Therefore: t=d/s

--------------------------------------------------

Time = Distance / Speed

Time = (15,000 metres) / (225 metres per minute)

--------------------------------------------------

Let's work it out:

Time=\frac { 15,000\quad metres }{ \frac { 225\quad metres }{ 1\quad minute\left( s \right)  }  } \\ \\ =\frac { 15,000\quad metres }{ 1 } \cdot \frac { 1\quad minute\left( s \right)  }{ 225\quad metres } \\ \\ =\frac { 15,000 }{ 225 } minutes

\\ \\ =\frac { 200 }{ 3 } minutes\\ \\ \frac { 200 }{ 3 } minutes\quad =\quad 66\quad minutes,\quad 40\quad seconds
6 0
4 years ago
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