All categories

2 years ago

What is 361.31 minus 2.841 equals blank?????? please help!!!

Mathematics

2 answers:

Digiron [165]2 years ago

8 0

<span>i think its 358.469 tell me if i wrong plz.

</span>

user100 [1]2 years ago

3 0

Line up the decimals. 361.3 10 Add a zero on the end - 2.841 ------------ Subtract 368.569 Your answer

You might be interested in

When the hour hand of a click goes around once, how many times does the minute hand of a clock go around?

stiv31 [10]

one hour = 60 minutes.

One day is 1440 minutes.

4 0

2 years ago

A map has a scale of ¾ inch represents 6 miles. If two towns are 32 miles apart, what is their distance apart on the map?

serious [3.7K]

3/4 in = 6 mi
? In = 32 miles

32 * 0.74 / 6 = 4 in
The distance apart is 4 in

7 0

2 years ago

Read 2 more answers

Mike and his dad are retiling his bathroom floor. They have budgeted $200 for the tiles and supplies. The tiles cost $1.85 each

Feliz [49]

Answer:

Equation: $114.90 + $1.85<em>x</em> = 200

Solution: They can buy 46 tiles.

Step-by-step explanation:

First, subtract 114.90 from both sides to get 1.85<em>x</em> = 85.10.

Divide 85.10 by 1.85 to get 46, which is the answer.

7 0

2 years ago

Write 9^6 as a power with a base of 3.

Elodia [21]

Sorry i dont know the answer

4 0

2 years ago

Read 2 more answers

H(x) = x2 1 k(x) = x – 2 (h k)(2) = (h – k)(3) = Evaluate 3h(2) 2k(3) =.

natima [27]

Quadratic equation is the equation in which only one variable is unknown. The highest power of the variable is 2.The value of the given functions are,

$(h+k)(x)=5$

$(h-k)(x)=9$

$3h(2)+2k(3)=17$

<h3>Given information-</h3>

The given function is,

$h(x)=x^2+1$

$k(x)=x-2$

<h3>Quadratic equation</h3>

Quadratic equation is the equation in which only one variable is unknown. The highest power of the variable is 2.

1) The value of the function (h+k)(2),

$(h+k)(x)=h(x)+k(x)$

$(h+k)(x)=x^2+1+x-2$

$(h+k)(2)=2^2+1+2-2$

$(h+k)(x)=5$

2)The value of the function (h-k)(3),

$(h-k)(x)=h(x)-k(x)$

$(h-k)(x)=x^2+1-x+2$

$(h-k)(3)=3^2+1-3+2$

$(h-k)(x)=9$

3) The value of the function 3h(2)+2k(3)

$3h(x)+2k(x)=3x^2+3+2x-2\times 2$

$3h(2)+2k(3)=3\times2^2+3+2\times2-2\times 2$

$3h(2)+2k(3)=17$

Hence the value of the given functions are,

$(h+k)(x)=5$

$(h-k)(x)=9$

$3h(2)+2k(3)=17$

Learn more about the quadratic equation here;

brainly.com/question/2263981

4 0

2 years ago