Conditional probablility P(A/B) = P(A and B) / P(B). Here, A is sum of two dice being greater than or equal to 9 and B is at least one of the dice showing 6. Number of ways two dice faces can sum up to 9 = (3, 6), (4, 5), (4, 6), (5, 4), (5, 5), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 10 ways. Number of ways that at least one of the dice must show 6 = (1, 6), (2, 6), (3, 6), (4, 6), (5, 6), (6, 6), (6, 5), (6, 4), (6, 3), (6, 2), (6, 1) = 11 ways. Number of ways of rolling a number greater than or equal to 9 and at least one of the dice showing 6 = (3, 6), (4, 6), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 7 ways. Probability of rolling a number greater than or equal to 9 given that at least one of the dice must show a 6 = 7 / 11
Well from what i see this equation isn't a point at all, however it does start at (0,0)
Answer:
The correct answer is -7.5 years.
Step-by-step explanation:
Given:
Principle amount = 12000
Interest = 4320
time = ?
rate = 4.8 simple interest
Solution:
We know that simple Interest I = (P*t*r)/100
then t = I*100/p*r
putting values in formula:
t = 4320*100/4.8*12000
= 432000/57,600
= 7.5 years
Answer:
x = 15
y = 5
Step-by-step explanation:
x = 15
y = 5
