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Greeley [361]
3 years ago
5

The lengths of the sides of a triangle are 3, 3, and the square root 3. Can the triangle be a right triangle?

Mathematics
2 answers:
Readme [11.4K]3 years ago
8 0
First find the decimal equivalent of square root 3: SQRT(3) = 1.732 ( roughly)
 
If the base and height were each 3, then the hypotenuse would need to be:

3^2 + 3^2 = C^2
9 + 9 = C^2
18 = C^2
C = SQRT(18) = 4.24

This is larger than sqrt(3), so this cannot be a right triangle.


If one leg was 3 and the other leg was sqrt(3) then the hypotenuse would be:
3^2 + 1.73^2 = C^2
9 + 3 = C^2
12 = C^2
C = SQRT(12) = 3.46

This is larger than 3, this cannot be a right triangle.

The answer is b) no.





melisa1 [442]3 years ago
8 0
No  
Because it does not obey Pythagoras theorem  (a^2 + b^2 = c^2)
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Hello from MrBillDoesMath!

Answer:

(x-8)^(1/3) +2

Discussion:

To find the inverse of a function swap the values of x and y in the original equation y = (x-2)^3 +8  and solve for y.

y = (x-2)^3 +8          =>  original function. swap x and y values

x = (y-2)^3 + 8        =>  subtract 8 from both sides

x - 8  = (y -2)^3        =>  take cube root of both sides

(x-8)^(1/3) = y - 2     => add 2 to both sides

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