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Greeley [361]
4 years ago
5

The lengths of the sides of a triangle are 3, 3, and the square root 3. Can the triangle be a right triangle?

Mathematics
2 answers:
Readme [11.4K]4 years ago
8 0
First find the decimal equivalent of square root 3: SQRT(3) = 1.732 ( roughly)
 
If the base and height were each 3, then the hypotenuse would need to be:

3^2 + 3^2 = C^2
9 + 9 = C^2
18 = C^2
C = SQRT(18) = 4.24

This is larger than sqrt(3), so this cannot be a right triangle.


If one leg was 3 and the other leg was sqrt(3) then the hypotenuse would be:
3^2 + 1.73^2 = C^2
9 + 3 = C^2
12 = C^2
C = SQRT(12) = 3.46

This is larger than 3, this cannot be a right triangle.

The answer is b) no.





melisa1 [442]4 years ago
8 0
No  
Because it does not obey Pythagoras theorem  (a^2 + b^2 = c^2)
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Answer:

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Given : $p=\frac{1}{1000}$

             = 0.001

The formulae of mean and variance are :

$\mu = \frac{1}{p}$

$\sigma ^2=\frac{q}{p^2}$

$\sigma ^2=\frac{1-p}{p^2}$

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              = $\mu = \frac{1}{0.001}$

              = 1000

  Variance =   $\sigma ^2=\frac{1-p}{p^2}$

                  = $\sigma ^2=\frac{1-0.001}{0.001^2}$

                           = 999,000

   The standard deviation is determined by the root of the variance.

    $\sigma = \sqrt{\sigma^2}$

        = $\sqrt{999,000}$ = 999.4999

b). We expect to have play lottery 1000  times to win, because the mean in part (a) is 1000.

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Expected value of the mean μ is the summation of a product of each of the possibility x with the probability P(x).

$\mu=\Sigma\ x\ P(x)= 499 \times 0.001+(-1) \times (1-0.001)$

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Since the answer is negative, we are expected to make a loss.

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