The graph of vector v with an initial point at (2, 6) and terminal point at
(5, -3). Thus, v = 3i - 9j represents the linear form of v.
<h3>How to find the vector component?</h3>
If we have given a vector v of initial point A and terminal point B
v = ai + bj
then the components form as;
AB = xi + yj
Here, xi and yj are the components of the vector.
c
Given;
The graph of vector v with an initial point at (2, 6) and terminal point at
(5, -3).
v = (5 - 2)i + (-3 - 6)j
v = (3)i + (-9)j
v = 3i - 9j
Thus, v = 3i - 9j represents the linear form of v.
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A^2 + b^2 = c^2
a^2 + (12)^2 = (13)^2
a^2 + 144 = 169
a^2 = 169 - 144
a^2 = 25
Sqrt (a^2) = Sqrt(25)
a = 5
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Answer:
x^2-10x+25
Step-by-step explanation:
(a+b)^2=a^2+2ab+b^2 so a=x and b=-5 so the expression is x^2-10x+25
Let the first number be x.
Therefore second number is (x+2).
Therefore third number is (x+4).
Therefore forth number is (x+6).
Hence,
(x+x+2+x+4+x+6+x+8)/4 = 15
(4x+12)/4 = 15
x+3 = 15
x = 12
So,
The number is 12, 14, 16, 18.
Hope it helps : )