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krok68 [10]
3 years ago
14

PLEASE HELP!!!!!

Mathematics
1 answer:
seraphim [82]3 years ago
6 0

Answer:

2,5,6,15

Step-by-step explanation:

that's what I think

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(PLEASE ANSWER: TIMED)The intensity, or loudness, of a sound can be measured in decibels (dB), according to the equation I(dB)=1
Mrac [35]
For this case we have the following equation:
 l(dB) = 10log( \frac{l}{lo} )
 We must replace the following value in the equation:
 l = 10^8lo
 Substituting we have:
 l(dB) = 10log( \frac{10^8lo}{lo} )
 Simplifying the given expression we have:
 l(dB) = 10log(10^8)
 Then, using logarithm properties in base 10, we can rewrite the expression:
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 Finally, making the product, the result is:
 l(dB) = 80
 Answer:
 
l(dB) = 80
 option 4
3 0
3 years ago
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What is (-14-x) squared in polynomial form?
Masteriza [31]
(-x-14)^2 = x^2 +14x+14x+196
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6 0
3 years ago
What is the value of the expression 12.25 + (-17.75)?
Reika [66]

Answer:

-5.5

Step-by-step explanation:

7 0
3 years ago
I need help with this asap!!! pls​
Len [333]

Answer:

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Step-by-step explanation:

1) unite rate

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4 0
3 years ago
(03.05 MC) Solve the rational equation x divided by 2 equals x squared divided by quantity x minus 2 end quantity, and check for
ycow [4]

Answer:

x = 0 and x = -2 are solutions of the given rational equation.

Step-by-step explanation:

We must solve the following rational equation:

\frac{x}{2} = \frac{x^{2}}{x-2}

Now we present the procedure:

1) \frac{x}{2} = \frac{x^{2}}{x-2} Given

2) x\cdot (x-2) = 2\cdot x^{2} Compatibility with multiplication/Existence of the multiplicative inverse/Definition of division/Modulative property.

3) x^{2}-2\cdot x = 2\cdot x^{2} Distributive property/a^{b}\cdot a^{c} = a^{b+c}

4) x^{2} + 2\cdot x = 0 Compatibility with addition/Existence of the additive inverse/Modulative property/Reflexive property

5) x \cdot (x+2) = 0 Distributive property/a^{b}\cdot a^{c} = a^{b+c}

6) x = 0\, \lor\, x = -2 Result

Now we check the rational equation with each root:

x = 0

\frac{x}{2} = \frac{x^{2}}{x-2}

\frac{0}{2} = \frac{0^{2}}{0-2}

0 = \frac{0}{-2}

0 = 0

x = 0 is a solution of the rational equation.

x = -2

\frac{x}{2} = \frac{x^{2}}{x-2}

\frac{-2}{2} =  \frac{(-2)^{2}}{-2-2}

-1 = -1

x = -2 is a solution of the rational equation.

4 0
3 years ago
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