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Vlad1618 [11]
3 years ago
11

Why does this series converge? ∞ ∑ (n+1)/[(n)(n+2)(n+3)] n=1

Mathematics
1 answer:
ollegr [7]3 years ago
6 0

Compare the series to the convergent series,

\displaystyle\sum_{n=1}^\infty\frac1{n^2}

By the limit comparison test, the given series converges because

\displaystyle\lim_{n\to\infty}\frac{\frac{n+1}{n(n+2)(n+3)}}{\frac1{n^2}}=\lim_{n\to\infty}\frac{n(n+1)}{(n+2)(n+3)}=1

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Complete question :

Suppose that of the 300 seniors who graduated from Schwarzchild High School last spring, some have jobs, some are attending college, and some are doing both. The following Venn diagram shows the number of graduates in each category. What is the probability that a randomly selected graduate has a job if he or she is attending college? Give your answer as a decimal precise to two decimal places.

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Answer:

0.56 ; 0.60

Step-by-step explanation:

From The attached Venn diagram :

C = attend college ; J = has a job

P(C) = (35+45)/300 = 80/300 = 8/30

P(J) = (30+45)/300 = 75/300 = 0.25

P(C n J) = 45 /300 = 0.15

1.)

P(J | C) = P(C n J) / P(C)

P(J | C) = 0.15 / (8/30)

P(J | C) = 0.5625 = 0.56

2.)

P(C | J) = P(C n J) / P(J)

P(C | J) = 0.15 / (0.25)

P(C | J) = 0.6 = 0.60

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Step-by-step explanation:

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