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just olya [345]
3 years ago
5

The credit remaining on a phone card (in dollars) is a linear function of the total calling time made with the card (in minutes)

. The remaining credit after 31 minutes of calls is $25.04 , and the remaining credit after 64 minutes of calls is $19.76 . What is the remaining credit after 85 minutes of calls?
Mathematics
1 answer:
Setler79 [48]3 years ago
7 0
Let the equation representing the function be y = -mx + c; where m is the charge per minute and c is a initial balance.
25.04 = -31m + c . . . . . (1)
19.74 = -64m + c . . . . . (2)
(1) - (2) gives: 5.3 = 33m
m = 5.3/33 = 0.16 (i.e. charge per minute is 16 cents)
From (1), 25.04 = -31(0.16) + c
25.04 = -4.96 + c
c = 25.04 + 4.96 = 30  (i.e. initial balance is $30)
Remaining credit after 85 minutes call is -85(0.16) + 30 = -13.6 + 30 = $16.40
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Consider this figure of a hexagon.
notsponge [240]
A)
It looks like the [irregular] hexagon has 3 rectangles and 2 triangles within it.
So let's exclude the triangular corners on bottom left and top right for now.
First we have a large rectangle covering most of the upper left of the polygon. 20 ft × 7 ft = 140 sq.ft.
Now we have a rectangle on the bottom right. The width is 11 ft, so take the 7 away from that, 4 ft. × 14 ft. on bottom. 4 ft × 14 ft = 56 sq.ft.
The last small rectangle fits on the right between the 2 other rectangles. It is 24-20 on top/bottom × 7-6 right/left. 4 ft × 1 ft = 4 sq.ft.
Now for the triangles: bottom left is 11-7 × 24-14 = 4 ft × 10 ft. 1/2bh = 1/2×10×4 = 20 sq.ft.
Top right is 24-20 × 11-5 = 4 ft × 6 ft. 1/2bh = 1/2×4×6 = 12 sq.ft.

B)
Add them all together for the total area (A):
A = 140 + 56 + 4 + 20 + 12 = 140+60+32
= 232 sq.ft.

Hope that explains it well enough! ;)
6 0
3 years ago
Read 2 more answers
The vertices of a square CDEF are C(1,1), D(3,1), E(3,-1) and F(1,-1). What formulas prove that the diagonals are congruent perp
Oxana [17]

To prove that the diagonals are congruent, you need to formula to compute the distance between two points:

d(A,B) = \sqrt{(A_x-B_x)^2 + (A_y-B_y)^2}

Using that formula, you may prove that d(C,E) = d(D,F), which means that the two diagonals have the same length.

To prove that they are perpendicular, you need the formula to compute the slope of a segment. The slope, knowing the enpoints, is given by

m = \cfrac{\Delta y}{\Delta x} = \cfrac{A_y-B_y}{A_x-B_x}

You can use this formula to prove that

m_{CE} = -\cfrac{1}{m_{DF}}

In fact, if one slope is the opposite of the reciprocal of the other, the two segments are perpendicular.

Finally, to prove that they bisect each other, you first need to find the point where they meet. First of all, you need to find the line the segments lie on: the formula is

y-y_0 = m(x-x_0)

where (x_0,y_0) is one of the points belonging to the line, and you already know how to find the slope. Then, you find the point of intersection, say A, by solving the system involving the two lines:

\begin{cases} y= m_{CE}x+q_{CE}\\ y = m_{DF}x+q_{DF} \end{cases}

And use again the formula for the distance between two points to prove that

d(A,C) = d(A,D) = d(A,E) = d(A,F)

4 0
3 years ago
If they are both right will give the thing and 5star if all are right btw
Vlad [161]

Answer:

The answer is

4. n ≤ −4

5. x ≤ −10

I hope this helps you

7 0
3 years ago
Read 2 more answers
Given the function g(x) = 8x − 2, compare and contrast g(−2) and g(4). Choose the statement that is true concerning these two va
stira [4]
The value of g(−2) is smaller than the value of g(4).
4 0
3 years ago
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George the Pigeon travels the same distance of 72 miles
NNADVOKAT [17]

Answer:

The speed of George the Pigeon in still air = 21 miles/hr

The speed of air = 3 miles/hr

Step-by-step explanation:

Let the speed of George the Pigeon in still air = u miles/hr

Let the speed of air = v miles/hr

Distance traveled = 72 miles

Relative speed against the wind = (u-v) miles/hr

Time taken against the wind = 4 hours

Relative speed with the wind = (u+v) miles/hr

Time taken against the wind = 3 hours

Using the formula:

Speed = \dfrac{Distance}{Time}

u-v=\dfrac{72}{4}\\\Rightarrow u-v=18 ..... (1)

u+v=\dfrac{72}{3}\\\Rightarrow u+v=24 ..... (2)

Adding (1) and (2):

2u=42\\\Rightarrow u = 21\ miles/hr

By equation (1):

v = 21-18\\\Rightarrow v = 3\ miles/hr

Therefore, the answer is:

The speed of George the Pigeon in still air = 21 miles/hr

The speed of air = 3 miles/hr

8 0
3 years ago
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