Answer:
A graph that has an axis of symmetry at x = 3 would be x^2 -6x + 12
Step-by-step explanation:
In order to find a graph that has an axis of symmetry at 3, use the equation for the axis of symmetry of a quadratic.
x = -b/2a
In this equation, a is the coefficient of x^2 and b is the coefficient of x. So, if we use 3 as x and we choose a random number to be a (1), we can solve for the b.
3 = -b/2(1)
3 = -b/2
6 = -b
b = -6
Now that we have this, we can put those two numbers as coefficients. The constant at the end can be anything.
Answer:
Step-by-step explanation:
X³ + 343 =
x³ + 7³ =
(x+7)(x²-7x+49)
3x-2y= -12
y=4x+1
3x-2(4x+1)= -12
3x-8x-2= -12
-5x=-12+2
-5x=-10
x= -10/-5
x=2
y=4x+1
y=4•2+1
y=8+1
y=9
(x,y) = (2,9)
