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3 years ago

How do I solve the equation

Mathematics

2 answers:

Citrus2011 [14]3 years ago

8 0

You didn’t put the equation

kaheart [24]3 years ago

7 0

Idk u can’t solve what u can’t see

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How do you do this and is this correct

loris [4]

Yes that is right so you just plug in the days as x then multiply the new x with the number to the left of it then add the number on the right and finally that is your y

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3 years ago

*EASY* WILL MARK BRAINEST! Find the slope of the line in the image below!

murzikaleks [220]

♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫

➷ Slope = rise/run

rise=2

run=1

Final answer:

2/1 or 2

✽

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

TROLLER

3 0

4 years ago

Read 2 more answers

Duncan is purchasing a home for $178,000. He makes a 15% down payment and obtains a 15 year fixed rate mortgage loan at 4% annua

KATRIN_1 [288]

1119.15×12=13,429.8 deposits per year
cost of principal
PVAO=13,429.8×((1−(1+0.04)^(−15))÷(0.04))=149,317.72
interest
13,429.8×15−149,317.72=52,129.28
down payment
178,000×0.15=26,700
intagible tax
178,000×0.002=356

Total cost
52,129.28+356+149,317.72+26,700
=228,503....answer

6 0

3 years ago

The rate of change of the downward velocity of a falling object is the acceleration of gravity (10 meters/sec 2) minus the accel

Alexus [3.1K]

Answer:

See below

Step-by-step explanation:

Write the initial value problem and the solution for the downward velocity for an object that is dropped (not thrown) from a great height.

if v(t) is the speed at time t after being dropped, v'(t) is the acceleration at time t, so the the initial value problem for the downward velocity is

v'(t) = 10 - 0.1v(t)

v(0) = 0 (since the object is dropped)

<em> The equation v'(t)+0.1v(t)=10 is an ordinary first order differential equation with an integrating factor </em>

$\bf e^{\int {0.1dt}}=e^{0.1t}$

so its general solution is

$\bf v(t)=Ce^{-0.1t}+100$

To find C, we use the initial value v(0)=0, so C=-100

and the solution of the initial value problem is

$\bf \boxed{v(t)=-100e^{-0.1t}+100}$

what is the terminal velocity?

The terminal velocity is

$\bf \lim_{t \to\infty}(-100e^{-0.1t}+100)=100\;mt/sec$

How long before the object reaches 90% of terminal velocity?

90% of terminal velocity = 90 m/sec

we look for a t such that

$\bf -100e^{-0.1t}+100=90\rightarrow -100e^{-0.1t}=-10\rightarrow e^{-0.1t}=0.1\\-0.1t=ln(0.1)\rightarrow t=\frac{ln(0.1)}{-0.1}=23.026\;sec$

How far has it fallen by that time?

The distance traveled after t seconds is given by

$\bf \int_{0}^{t}v(t)dt$

So, the distance traveled after 23.026 seconds is

$\bf \int_{0}^{23.026}(-100e^{-0.1t}+100)dt=-100\int_{0}^{23.026}e^{-0.1t}dt+100\int_{0}^{23.026}dt=\\-100(-e^{-0.1*23.026}/0.1+1/0.1)+100*23.026=1,402.6\;mt$

3 0

3 years ago

Which of the following has six faces?

Goryan [66]

Answer:

Step-by-step explanation:

Hexa means six, so a hexahedron is a figure with six faces. Therefore, choice D is the correct answer.

7 0

3 years ago