3 years ago

How do I solve the equation

Mathematics

2 answers:

Citrus2011 [14]3 years ago

8 0

You didn’t put the equation

kaheart [24]3 years ago

7 0

Idk u can’t solve what u can’t see

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Expand the following using the Binomial Theorem and Pascal’s triangle (2x − 3y)^4

krok68 [10]

Answer:

Step-by-step explanation:

Binomial Expansion:

$(2x-3y)^4 \\\\= 4C_0(2x)^4 (-3y)^0 + 4C_1(2x)^3 (-3y)^1 + 4C_2(2x)^2(-3y)^2 \\\\+ 4C_3(2x)^1 (-3y)^3 + 4C_4(2x)^0 (-3y)^4\\\\=16x^4 + 4(8x^3)(-3y) + 6(4x^2)(9y^2) + 4(2x)(-27y^3) + 81y^4\\\\=16x^4 - 96x^3y + 216x^2y^2-216xy^3 +81y^4$

Pascal's Triangle:

Zero row 1

First row 1 1

Second row 1 2 1

Third row 1 3 3 1

Fourth row 1 4 6 4 1

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3 years ago

Joe can run twice as fast as Pete. They start at the same point and run in opposite directions for 40 minutes. The distance betw

Vesnalui [34]

I don't know you nswer po

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3 years ago

5/8 minus negative 2/8<br> 5/8 - (-2/8)

blsea [12.9K]

I hope this helps you

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3 years ago

-3/4 / (-8/5) write in simplest form

Shkiper50 [21]

Answer:

Ans = 15/32

Step-by-step explanation:

-3/4 / (-8/5)

= -3/4 ÷ (-8/5)

= -3/4 * -5/8

= 15/32 (- * - = +)

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4 years ago

A right cylinder is inscribed in a sphere of radius r. How do you find the largest possible volume of such a cylinder?

satela [25.4K]

Answer:

Step-by-step explanation:

Suppose Radius of sphere is R and cylinder inscribed inside the sphere is r with height h

using Pythagoras theorem in shown triangle

$R^2=r^2+(\frac{h}{2})^2$

$r^2=R^2-(\frac{h}{2})^2$

Volume of cylinder is

$V=\pi \times r^2\times h$

$V=\pi \times (R^2-(\frac{h}{2})^2)\times h$

$V=\pi (R^2\cdot h-\frac{h^3}{4})$

differentiate V w.r.t to h we get

$\frac{\mathrm{d} V}{\mathrm{d} h}=\pi (R^2-\frac{3h^2}{4})$

Putting $\frac{\mathrm{d} V}{\mathrm{d} h}$ to get maxima/minima

$R^2=\frac{3h^2}{4}$

$h=\frac{2R}{\sqrt{3}}$

therefore radius r is given by

$r=\sqrt{\frac{2R}{3}}$

therefore volume is given by

$V=\frac{4}{3\sqrt{3}}\pi R^3$

5 0

3 years ago