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Naddik [55]
3 years ago
8

Solve this equation 4log√x - log 3x =log x^2​

Mathematics
1 answer:
ruslelena [56]3 years ago
5 0

Answer:

x =  \frac{1}{3}

Step-by-step explanation:

*Move terms to the left and set equal to zero:

4㏒(√x) - ㏒(3x) - ㏒(x²) = 0

*simplify each term:

㏒(x²) - ㏒(3x) - ㏒(x²)

㏒(x²÷x²) -㏒(3x)

㏒(x²÷x² / 3x)

*cancel common factor x²:

㏒(\frac{1}{3x})

*rewrite to solve for x :

10⁰ = \frac{1}{3x}

1 = \frac{1}{3x}

1 · x = \frac{1}{3x} · x

1x = \frac{1}{3}

*that would be our answer, however, the convention is to exclude the "1" in front of variables so we are left with:

x = \frac{1}{3}

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<h3>What is LCM ?</h3>

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It is asked to determine

LCM of 6 and 9

6 = { 6 , 12 , 18 , 24 , 30 , 36 , 42 .....}

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The LCM of 8 and 12 is 24

LCM of 4 , 6 and 8

4 = {4 , 8 , 12 , 16 , 20,24,28 ....}

6 = { 6 ,12 ,18,24......}

8 = {8 , 16,24 .....}

The LCM of 4,6 and 8  is 24

The LCM of 6 and 15 is 30  

The LCM of 20 and 30 is  60

The LCM of 25,30 and 75 is 150

The image of the solution is attached .

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brainly.com/question/20739723

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