Answer:
10% of progeny would have wild type phenotype
Explanation:
True breeding fly with wild type wings and small eyes: De/De
True breeding fly with downward wings and wild type eyes: dE/dE
Cross between them : De/De X dE/dE = De/dE ( F1 )
Recombination frequency = 20%
Next cross, De/dE X de/de =
De/de = parental = 40%
dE/de = parental = 40%
DE/de = recombinant = 10%
de/de = recombinant = 10%
The third genotype i.e. one of the recombinant genotypes will have the wild type makeup ( DE/de ) hence 10% of flies would have wild type phenotype.
C seems like the correct answer
Answer:
increasing extension time
Explanation:
The Polymerase Chain Reaction is a technique widely used in molecular biology laboratories to amplify target DNA regions. The standard steps of a PCR are as follow 1-denaturation, 2-annealing and 3-elongation/extension. These steps are repeated 15-40 times in order to exponentially amplify the linear DNA fragment. It is well known that longer extension times can be used as a strategy to increase the yield of longer PCR products. This is because the extension time depends on the synthesis rate of the DNA polymerase used in PCR technique and the length of the DNA fragment to be amplified.
