Answer:
There is no specific linear equation for this scenario because there is only one possible length for the pole.
Step-by-step explanation:
Answer:
No Real Solutions.
Step-by-step explanation:
√(x-5)=8√(x-2)
Square on both sides,
(√(x-5))^2=(8√(x-2))^2
or,(x-5)=64(x-2)
or,x-5=64x-128
or,-5+128=64x-x
or,123/63=x
Therefore, x=41/21
If you plug x=41/21 in √(x-5)=8√(x-2) you do not get equals, so the problem has no real solutions.
Answer:
The discriminant is 0
There is 1 real solution
Step-by-step explanation:
Use the discriminant formula, D = b² - 4ac
In the equation y = x² - 4x + 4, a is 1, b is -4, and c is 4.
Plug in these values into the formula:
D = b² - 4ac
D = (-4)² - 4(1)(4)
D = 16 - 4(4)
D = 16 - 16
D = 0
So, the discriminant is 0.
With a discriminant of zero, there is one real solution.
So, the number of real solutions is 1.
H(x) = 16 - x
plug -4 in as x
H(x) = 16 - (-4)
solve 16 - (-4)
H(x) = 20
your answer is A)20
