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Tresset [83]
3 years ago
9

When 10g of calcium carbonate is heated,4.4g of carbon dioxide escape out. The amount of residue left is:

Chemistry
1 answer:
Maslowich3 years ago
8 0
The dissociation of calcium carbonate, CaCO3, to simpler compounds can be expressed as,
                        CaCO3 --> CaO + CO2
The precipitate is CaO and its amount is calculated through the difference which will give us the answer of 5.6 g. 
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PLEASE HELP ME!
n200080 [17]

Answer:

"Calculate" (and any subsequent words) was ignored because we limit queries to 32 words.

5 0
3 years ago
Now we need to find the amount of NF3 that can be formed by the complete reactions of each of the reactants. If all of the N2 wa
Alex777 [14]

The question is incomplete, the complete question is:

Nitrogen and fluorine react to form nitrogen fluoride according to the chemical equation:

N_2(g)+3F_2(g)\rightarrow 2NF_3(g)

A sample contains 19.3 g of N_2 is reacted with 19.3 g of F_2. Now we need to find the amount of NF_3 that can be formed by the complete reactions of each of the reactants.

If all of the N_2 was used up in the reaction, how many moles of NF_3 would be produced?

<u>Answer:</u> 1.378 moles of NF_3 are produced in the reaction.

<u>Explanation:</u>

The number of moles is defined as the ratio of the mass of a substance to its molar mass.

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}       ......(1)

Limiting reagent is defined as the reagent which is completely consumed in the reaction and limits the formation of the product.

Excess reagent is defined as the reagent which is left behind after the completion of the reaction.

In the given chemical reaction, N_2 is considered as a limiting reagent because it limits the formation of the product and it was completely consumed in the reaction.

We are given:

Mass of N_2 = 19.3 g

Molar mass of N_2 = 28.02 g/mol

Putting values in equation 1:

\text{Moles of }N_2=\frac{19.3g}{28.02g/mol}=0.689mol

For the given chemical reaction:

N_2(g)+3F_2(g)\rightarrow 2NF_3(g)

By the stoichiometry of the reaction:

1 mole of N_2 produces 2 moles of NF_3

So, 0.689 moles of N_2 will produce = \frac{2}{1}\times 0.689=1.378mol of NF_3

Hence, 1.378 moles of NF_3 are produced in the reaction.

8 0
3 years ago
5 points
podryga [215]

Answer:

the answer would be A have good day

Explanation:

pls mark brainliest and 5 stars

<3

7 0
2 years ago
Which three of the following are steps of aerobic cellular respiration?
aleksley [76]
A.
C.
D. 

Are the answers. 

Hope this helps. :)
3 0
3 years ago
How do the internal structures of vascular and plants transport food and water.
mariarad [96]
All vascular plants have vascular tissue which allows the transport of water, nutrients and food between the ground and the body of the plant. So your answer would be that the internal structures of vascular plants transport food and water through their vascular tissue. Hope this helps!<span />
4 0
3 years ago
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