A serial dilution is the stepwise dilution of a substance in solution. Usually the dilution factor at each step is constant, resulting in a geometric progression of the concentration in a logarithmic fashion.
The given reaction is:
C4H10 + O2 → CO2 + H2O
The above equation is not balanced due to the unequal distribution of atoms on either side of equation
# atoms Reactants # atoms products
C = 4 C = 1
H = 10 H = 2
O = 2 O = 3
In order to balance it, multiply C4H10 by 2, O2 by 13, CO2 by 8 and H2O by 10 to get:
2C4H10 + 13 O2 → 8CO2 + 10H2O
Single bonds are those that bond with one atom, and sigma bonds are the strongest type of covalent bonds that are single bonded.
That means NO, not all single bonds are sigma bond, but all sigma bonds are single bonds.
If more acetic acid were added to a solution at equilibrium, [H⁺] and [CH₃CO₂⁻] would increase to counteract the perturbation. (Option C)
<h3>How do systems at equilibrium respond to perturbation?</h3>
When a system at equilibrium suffers a perturbation, it shifts its equilibrium position to counteract such perturbation.
Let's consider a solution of acetic acid at equilibrium.
CH₃CO₂H(aq) = CH₃CO₂⁻(aq) + H⁺(aq)
If more acetic acid were added to the solution, the system will shift toward the products to counteract such an increase.
How would the system change if more acetic acid were added to the solution?
A. [H⁺] would decrease and [CH₃CO₂⁻] would increase. NO.
B. [H⁺] and [CH₃CO₂⁻] would decrease. NO.
C. [H⁺] and [CH₃CO₂⁻] would increase. YES. Both products would increase.
D. [H⁺] would increase and [CH₃CO₂⁻] would decrease. NO.
If more acetic acid were added to a solution at equilibrium, [H⁺] and [CH₃CO₂⁻] would increase to counteract the perturbation.
Learn more about equilibrium here: brainly.com/question/2943338
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