(7.3 x 10^29 atoms) / (24 atoms/molecule) / (6.022 x 10^23 molecules/mol) =
5.1 x 10^4 mol C6H12O6
The third question requires you to solve for the weight of sodium (Na) and weight of Chloride (Cl) from the calculated moles of each element Na, and Cl.
So, you need to multiply the calculated moles of Na with its molar mass (23 g/ mol) to get the answer for Na. And multiply the calculated moles of Cl with its molar mass (35.45 g/mol) to get the answer for Cl.
15.9643 gramns are in 2.3 moles of lithium
The theoretical yield of Ca(OH)₂ : 42.032 g
<h3>Further explanation</h3>
Given
31.8 g of CaO
Required
The theoretical yield of Ca(OH)₂
Solution
Reaction
CaO + H₂O⇒Ca(OH)₂
mol CaO (MW=56 g/mol) :
= mass : MW
= 31.8 g : 56 g/mol
= 0.568
From equation, mol Ca(OH)₂ = mol CaO = 0.568
Mass Ca(OH)₂ (MW=74 g/mol) :
= 0.568 x 74
= 42.032 g
