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ExtremeBDS [4]
3 years ago
9

For each reaction, identify the element that gets reduced and the element that gets oxidized. 2 AgCl + Zn ⟶ 2 Ag + ZnCl 2 2AgCl+

Zn⟶2Ag+ZnCl2 Identify the element that gets reduced. chlorine silver zinc Identify the element that gets oxidized. chlorine silver zinc 4 NH 3 + 3 O 2 ⟶ 2 N 2 + 6 H 2 O 4NH3+3O2⟶2N2+6H2O Identify the element that gets reduced. oxygen hydrogen nitrogen Identify the element that gets oxidized. hydrogen oxygen nitrogen Fe 2 O 3 + 2 Al ⟶ Al 2 O 3 + 2 Fe Fe2O3+2Al⟶Al2O3+2Fe Identify the element that gets reduced. aluminum oxygen iron Identify the element that gets oxidized. oxygen iron aluminum
Chemistry
1 answer:
Mnenie [13.5K]3 years ago
4 0

Answer:

Explanation:

Oxidation:

Oxidation involve the removal of electrons and oxidation state of atom of an element is increased.

Reduction:

Reduction involve the gain of electron and oxidation number is decreased.

Oxidizing agents:

Oxidizing agents oxidize the other elements and itself gets reduced.

Reducing agents:

Reducing agents reduced the other element are it self gets oxidized.

Consider the following reaction:

2AgCl + Zn  → 2Ag + ZnCl₂

In this reaction oxidation state of Zn on left side is 0 while on right side +2 so it gets oxidized and oxidation state of Ag on left side is +1 and on right side 0 so it get reduced.

4NH₃  +  3O₂   →   2N₂ +  6H₂O

In this reaction oxidation state of nitrogen on left side is -3 while on right side 0 so it gets oxidized and oxidation state of oxygen on left side is 0 and on right side -2 so it get reduced.

Fe₂O₃ +  2Al  →   Al₂O₃ +  2Fe

In this reaction oxidation state of iron on left side is +3 while on right side 0 so it gets reduced and oxidation state of Al on left side is 0 and on right side +3 so it get oxidized.

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what is the concentration of hydroxide ions after 50.0 ml of 0.250 m naoh is added to 120 ml of 0.200 m na2so4? please show all
Galina-37 [17]

The concentration of the hydroxide ions after 50 ml of 0.250M NaOH is added to 120ml of 0.200M Na2SO4 is 7.35 x 10^-2 M.

What is meant by concentration?

Concentration is the total amount of solute present in the given volume of solution. this is expressed in terms of molarity, molality, mole fraction, normality etc. The term concentration mostly refers to the solvents and solutes present in the solution.

Concentration of hydroxide ions can be calculated by,

M (OH^-) = V (NaOH) x M (NaOH) / V (total) = 50ml x 0.250M / 50ml + 120ml = 0.0735M = 7.35 x 10^-2 M.

where M (OH^-) = concentration of hydroxide ions, V(NaOH) = volume of NaOH, M(NaOH) = concentration of NaOH.

Therefore, the concentration of the hydroxide ions after 50 ml of 0.250M NaOH is added to 120ml of 0.200M Na2SO4 is 7.35 x 10^-2 M.

To learn more about concentration click on the given link brainly.com/question/17206790

#SPJ4

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When magnesium loses it's valence electrons, it has the atomic structure of what element?
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