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ExtremeBDS [4]
3 years ago
9

For each reaction, identify the element that gets reduced and the element that gets oxidized. 2 AgCl + Zn ⟶ 2 Ag + ZnCl 2 2AgCl+

Zn⟶2Ag+ZnCl2 Identify the element that gets reduced. chlorine silver zinc Identify the element that gets oxidized. chlorine silver zinc 4 NH 3 + 3 O 2 ⟶ 2 N 2 + 6 H 2 O 4NH3+3O2⟶2N2+6H2O Identify the element that gets reduced. oxygen hydrogen nitrogen Identify the element that gets oxidized. hydrogen oxygen nitrogen Fe 2 O 3 + 2 Al ⟶ Al 2 O 3 + 2 Fe Fe2O3+2Al⟶Al2O3+2Fe Identify the element that gets reduced. aluminum oxygen iron Identify the element that gets oxidized. oxygen iron aluminum
Chemistry
1 answer:
Mnenie [13.5K]3 years ago
4 0

Answer:

Explanation:

Oxidation:

Oxidation involve the removal of electrons and oxidation state of atom of an element is increased.

Reduction:

Reduction involve the gain of electron and oxidation number is decreased.

Oxidizing agents:

Oxidizing agents oxidize the other elements and itself gets reduced.

Reducing agents:

Reducing agents reduced the other element are it self gets oxidized.

Consider the following reaction:

2AgCl + Zn  → 2Ag + ZnCl₂

In this reaction oxidation state of Zn on left side is 0 while on right side +2 so it gets oxidized and oxidation state of Ag on left side is +1 and on right side 0 so it get reduced.

4NH₃  +  3O₂   →   2N₂ +  6H₂O

In this reaction oxidation state of nitrogen on left side is -3 while on right side 0 so it gets oxidized and oxidation state of oxygen on left side is 0 and on right side -2 so it get reduced.

Fe₂O₃ +  2Al  →   Al₂O₃ +  2Fe

In this reaction oxidation state of iron on left side is +3 while on right side 0 so it gets reduced and oxidation state of Al on left side is 0 and on right side +3 so it get oxidized.

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How can one determine if a bond between two atoms is ionic covalent or metallic?
Wewaii [24]

Answer:

By the Pauling rule, of EN

Explanation:

EN means electronegativity, the ability of atoms to attract electrons.

In the periodic table each atom, has a value of EN.

When there are two atoms bonded, you must substract the EN (the high - the low) → ΔEN

It depends on the ΔEN, that you can define a bond as ionic, covalent or metallic.

Ionic ΔEN → > 1.7

Covalent polar 0.4 < ΔEN > 1.7

Covalent non polar 0.4 < ΔEN

Two metals have always a metallic bond

5 0
3 years ago
What is relative mass of an atom
kow [346]

Answer:

Explanation:

The relative atomic mass of an element is a weighted average of the masses of the atoms of the isotopes - because if there is much more of one isotope then that will influence the average mass much more than the less abundant isotope will.

8 0
3 years ago
Which salt shows the least solubility change when the temperature is increased from 0 to 100 c?
Hunter-Best [27]
Sodium chloride (NaCl), whose only changes about 5g/100mL water over that entire range 100°C)
4 0
3 years ago
Read 2 more answers
Which pair of molecules is not a polar bond?<br> OA. N-O<br> OO<br> B. C-O<br> C.O-H<br> OD. 0-0
hodyreva [135]
Od. 0-0 does not pair of the Molecules bid it’s polar bond due to certain pairs of molecules not being present within its presentations
4 0
3 years ago
A titration of 25.0 mL of a solution of the weak base aniline, C6H5NH2, requires 25.67 mL of 0.175 M HCl to reach the equivalenc
Lorico [155]

Answer:

a. 0.180M of C₆H₅NH₂

b. 0.0887M C₆H₅NH₃⁺

c. pH = 2.83

Explanation:

a. Based in the chemical equation:

C₆H₅NH₂(aq) + HCl(aq) → C₆H₅NH₃⁺(aq) + Cl⁻(aq)

<em>1 mole of aniline reacts per mole of HCl</em>

Moles required to reach equivalence point are:

Moles HCl = 0.02567L ₓ (0.175mol / L) = 4.492x10⁻³ moles HCl = moles C₆H₅NH₂

As the original solution had a volume of 25.0mL = 0.0250L:

4.492x10⁻³ moles C₆H₅NH₂ / 0.0250L = 0.180M of C₆H₅NH₂

b. At equivalence point, moles of C₆H₅NH₃⁺ are equal to initial moles of C₆H₅NH₂, that is 4.492x10⁻³ moles

But now, volume is 25.0mL + 25.67mL = 50.67mL = 0.05067L. Thus, molar concentration of C₆H₅NH₃⁺ is:

[C₆H₅NH₃⁺] = 4.492x10⁻³ moles / 0.05067L = 0.0887M C₆H₅NH₃⁺

c. At equivalence point you have just 0.0887M C₆H₅NH₃⁺ in solution. C₆H₅NH₃⁺ has as equilibrium in water:

C₆H₅NH₃⁺(aq) + H₂O(l) → C₆H₅NH₂ + H₃O⁺

Where Ka = Kw / Kb = 1x10⁻¹⁴ / 4.0x10⁻¹⁰ =

<em>2.5x10⁻⁵ = [C₆H₅NH₂] [H₃O⁺] / [C₆H₅NH₃⁺]</em>

When the system reaches equilibrium, molar concentrations are:

[C₆H₅NH₃⁺] = 0.0887M - X

[C₆H₅NH₂] = X

[H₃O⁺] = X

Replacing in Ka formula:

2.5x10⁻⁵ = [X] [X] / [0.0887M - X]

2.2175x10⁻⁶ - 2.5x10⁻⁵X = X²

0 = X² + 2.5x10⁻⁵X - 2.2175x10⁻⁶

Solving for X:

X = -0.0015 → False solution. There is no negative concentrations.

X = 0.001477 → Right solution.

As [H₃O⁺] = X, [H₃O⁺] = 0.001477

Knowing pH = -log [H₃O⁺]

pH = -log 0.001477

<h3>pH = 2.83</h3>

7 0
3 years ago
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