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julsineya [31]
3 years ago
12

What is an exponent for 147

Mathematics
1 answer:
Yuri [45]3 years ago
5 0
147 is not a prime number 147= 49 * 3
49 is divisable by 7: 49= 7 * 7
7 is not divisable by anything
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Read 2 more answers
P is the incenter of △JKL. Find m∠JKP.<br> &amp; can you please explain
dangina [55]

Answer:

  • m∠MKP = 35°

Step-by-step explanation:

<u>Incenter is the intersection of angle bisectors.</u>

  • ∠MJP = ∠OJP, ∠MKP = ∠NKP, ∠NLP = ∠OLP

<u>First find the value of x:</u>

  • 7x - 6 = 5x + 4
  • 7x - 5x = 4 + 6
  • 2x = 10
  • x = 5

<u>Find the angle MJP:</u>

  • 7*5 - 6 = 29°

<u>We know sum of interior angles of a triangle is 180°. Using this find the missing angle measure:</u>

  • 2*m∠MJP + 2*m∠NJP + 2*m∠MKP = 180°
  • m∠MJP + m∠NJP + m∠MKP = 90°
  • 29° + 26° + m∠MKP = 90°
  • m∠MKP = 90° - 55°
  • m∠MKP = 35°
7 0
3 years ago
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