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PolarNik [594]
3 years ago
10

What is the relationship between the range and the equation of the asymptote

Mathematics
1 answer:
nadezda [96]3 years ago
7 0

Vertical asymptotes are vertical lines which correspond to the zeroes of the denominator of a rational function<span>. (They can also arise in other contexts, such as logarithms, but you'll almost certainly first encounter asymptotes in the context of rationals.)  I'll give you an example:
</span>


 

This is a rational function. More to the point, this is a fraction. Can you have a zero in the denominator of a fraction? No. So if I set the denominator of the above fraction equal to zero and solve, this will tell me the values that x cannot be:

x2 – 5x – 6 = 0<span>
</span>(x – 6)(x + 1) = 0<span>
</span>x = 6 or –1

So x cannot be 6 or –1, because then I'd be dividing by zero.


<span>  <span><span> <span> </span></span><span><span /><span>
</span> </span> </span></span>

The domain is the set of all x-values that I'm allowed to use. The only values that could be disallowed are those that give me a zero in the denominator. So I'll set the denominator equal to zero and solve.

<span>x2 + 2x – 8 = 0</span><span>
</span><span>(x + 4)(x – 2) = 0</span><span>
</span><span>x = –4</span> or <span>x = 2</span>

Since I can't have a zero in the denominator, then I can't have <span>x = –4</span> or <span>x = 2</span> in the domain. This tells me that the vertical asymptotes (which tell me where the graph can <span>not </span>go) will be at the values <span>x = –4</span> or <span>x = 2</span>.

domain:  <span>
</span><span>vertical asymptotes:  <span>x = –4</span>,<span> 2</span></span> <span> <span>   </span></span>


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Hey there!

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chubhunter [2.5K]

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triangle QRS is an equilateral triangle. If QR is seventeen more than twice x, RS is 19 less than six times x, and QS is one les
koban [17]

Value of x is 9 and measure of each side is 35 units.

<u>SOLUTION: </u>

Given, Triangle QRS is an equilateral triangle.  

QR is seventeen more than twice x, \rightarrow QR = 17 + 2x

RS is 19 less than six times x, \rightarrow RS = 6x-19

And QS is one less four times x, \rightarrow QS = 4x-1

We have to find x and measure of each side.

Now, we know that, sides of equilateral triangle are equal,  

Then QR = QS \rightarrow 17 + 2x = 4x-1 \rightarrow 4x-2x = 17 + 1 \rightarrow 2x = 18 \rightarrow x = 9

So, value of x is 9.

\begin{array}{l}{\text { Now, } \mathrm{QR}=17+2(9)=17+18=35} \\\\ {\mathrm{RS}=6(9)-19=54-19=35} \\\\ {\mathrm{QS}=4(9)-1=36-1=35}\end{array}

Hence, value of x is 9 and measure of each side is 35.

5 0
4 years ago
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