Answer:
Mr. devito needs to buy 40 packs
Step-by-step explanation:
Given:
Total number of fourth grade students = 118
The number of pencils in one pack = 6
The number pencil each student gets =2
To find:
The number of packs of pencils that is to be bought = ?
Solution:
To give all the 118 fourth grade students each 2 pencils , the total number of pencils needed will be
= > ![118 \times 2](https://tex.z-dn.net/?f=118%20%5Ctimes%202)
=> 236 Pencils
We know that a pack contains 6 pencils, so the number of pack that has to be bought , in order to have 236 pencils will be
=> ![\frac{ \text{total number of pencils}}{\text{ number of pencils per pack }}](https://tex.z-dn.net/?f=%5Cfrac%7B%20%5Ctext%7Btotal%20number%20of%20pencils%7D%7D%7B%5Ctext%7B%20number%20of%20pencils%20per%20pack%20%7D%7D)
On substituting the values
=> ![\frac{236}{6}](https://tex.z-dn.net/?f=%5Cfrac%7B236%7D%7B6%7D)
=> 39.33
=> 40
Answer:
x = 9, y = 27
Step-by-step explanation:
Since the figures are similar then the ratios of corresponding sides are equal, that is
=
( cross- multiply )
12(x - 1) = 96 ( divide both sides by 12 )
x - 1 = 8 ( add 1 to both sides )
x = 9
Also
=
( cross- multiply )
12(y + 1) = 336 ( divide both sides by 12 )
y + 1 = 28 ( subtract 1 from both sides )
y = 27
Answer:
x=1
y=-1
Step-by-step explanation:
hope it will help you
Answer: 3x=3
Step-by-step explanation: Let's divide this into parts--
1. Adding the x variables: -2x+5x or 5x-2x = 3x.
2. Adding the y variables: y-y or -y+y = 0. (The negative and the positive y cancel each other out.)
3. Adding the numbers: 8-5 or -5+8 = 3.
Now just put it back into an equation: 3x + 0 = 3.
We don't need to add the 0, so the equation changes into 3x = 3.