Two distinct concentric circles never intersects each other . Hence it does not have any solutions. As we know that the two parabolas intersect at a maximum of Two Points.
Answer:
Angle 1 = 119 degrees.
Step-by-step explanation:
3x + 31 = 6x + 1 (exterior alternate angles)
30 = 3x
x = 10
So the angle marked 6x + 1 = 6(10)+1
= 61
Angle 1 is adjacent to this so it is 180-61 = 119 degrees.
You can double the fractions, so instead of 14/20 and 15/20 you have 28/40 and 30/40. The fractions still equal the same amount. Between theses two new fractions is the fraction 29/40.
So, 29/40 is between 14/20 and 15/20.
The answer is there are no solutions because i just had that question and put it AND IT WAS RIGHT..
Answer:
20sets
Step-by-step explanation:
Since we are to select 3 unordered letters from the word q, u, a, k, e, s, we will apply the combination rule.
For example if r objects are to be selected from n pool of objects, this can be done in nCr number of ways.
nCr = n!/(n-r)!r!
Since the total number of letter in the word q, u, a, k, e, s is 6letters and we are to form 3 letters from it unordered, this can be done in 6C3 number of ways.
6C3 = 6!/(6-3)!3!
6C3 = 6!/3!3!
6C3 = 6×5×4×3×2×1/3×2×1×3×2×1
6C3 = 6×5×4/3×2
6C3 = 120/6
6C3 = 20
Hence 20sets of selection are possible