Question

A company produces packages of granola and has changed its recipe. It claims that the proportion of almonds in how is the appropriate test statistic calculated?

Answer 1

Answer:

The correct answer is

$t = \frac{0.49-0.29}{\sqrt{\frac{(0.42)^2}{100} +}\frac{(0.29)^2}{100} }$

Step-by-step explanation:

To solve the question we note that the question involves a test statistic calculation given by

$t = \frac{x_1-x_2}{\sqrt{\frac{s_1^2}{n_1} +}\frac{s_2^2}{n_2} }$ Where

x₁ = Mean of sample 1

x₂ = Mean of sample 2

n₁ = Sample size of sample 1

n₂ = Sample size of sample 2

s₁ = Variance of sample 1

s₂ = Variance of sample 2

s₁ = ∑(x₁ - x₁')²/n₁,  s₂ = ∑(x₂ - x₂')²/n₂

The test statistic is a variable that is derived from a given data sample and is applied in hypothesis testing. The test statistic measures the available data against the expected value from the null hypothesis

With the given data, we have

$t = \frac{0.49-0.29}{\sqrt{\frac{(0.42)^2}{100} +}\frac{(0.29)^2}{100} }$