There are 16 ounces in a pound
62/16 = 3 pounds 14 ounces
Hope this helps!
Answer:
Power: (1/5)^3, 2^6
Expanded: 5x5, 6x6x6, 3x3x3/4, 2x2x2x2x2x2
How to say it: 5 raised to the 2nd power, 6 raised to the 3rd power, 3 raised to the 3rd power over 4
Value: 25, 216, 1/125, 9/4, 64
Step-by-step explanation:
Answer:
x=5, y=2, z=2
Step-by-step explanation:
y=3x-13
-3x+4y+2z = -3x + 4(3x-13) + 2z = 9x+2z-52 = -3
9x + 2z = 49 ... (1)
2x-4y-z = 2x-4(3x-13)-z = -10x-z+52 = 0
10x + z = 52 ... (2)
(2)*2-(1): 11x = 55 <u>x = 5</u>
y = 3x-13 = 15-13 = 2 <u>y=2</u>
z = (49-9x) / 2 = 2 <u>z = 2</u>
We need a system of equations to solve this. "Difference" is to subtract, and we are taking this difference of the 2 squared unknowns to be 20. That equation is
![x^{2} -y^2=20](https://tex.z-dn.net/?f=%20x%5E%7B2%7D%20-y%5E2%3D20)
. Our "first number is x^2, so 3 times that is 3x^2. "Increased by" is adding to that first number. What we are adding is the second number. The second equation is
![3x^2+y^2=124](https://tex.z-dn.net/?f=3x%5E2%2By%5E2%3D124)
. Let's solve the first equation for x^2:
![x^2=y^2+20](https://tex.z-dn.net/?f=x%5E2%3Dy%5E2%2B20)
and sub that value for x^2 into the second equation.
![3(y^2+20)+y^2=124](https://tex.z-dn.net/?f=3%28y%5E2%2B20%29%2By%5E2%3D124)
and
![3y^2+60+y^2=124](https://tex.z-dn.net/?f=3y%5E2%2B60%2By%5E2%3D124)
. Subtract 60 from both sides and combine the y^2 terms to get
![4y^2=64](https://tex.z-dn.net/?f=4y%5E2%3D64)
. Divide both sides by 4 to get y^2 = 16 and y = 4. Let's go back now and solve for x. We will use the fact that y^2 = 16 to solve for x^2 and then take the square root of it.
![x^2-16=20](https://tex.z-dn.net/?f=x%5E2-16%3D20)
, x^2 = 4, so x = 2. Your solutions are x = 2 and y = 4. There you go!