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viva [34]
3 years ago
6

A 3 inch radius circle is drawn inside a 7 inch radius circle. If you throw a dart at these circles, what is the probability you

land inside the bigger circle but outside smaller circle?
Mathematics
1 answer:
lorasvet [3.4K]3 years ago
3 0

Answer:

Step-by-step explanation:

The first step is to determine the areas of the inner and the bigger circles.

The formula for determining the area of a circle is expressed as

Area = πr²

Where

r represents the radius of the circle.

π is a constant whose value is 3.14

Considering the inner circle,

diameter = 148.4 cm

Radius = 3 inches

Area = 3.14 × 3² = 28.26 inches²

Considering the bigger circle,

Radius = 7 inches

Area = 3.14 × 7² = 153.86 inches²

The area between the bigger and inner circles is

153.86 - 28.26 = 125.6 inches²

Probability = number of favourable outcome/number of total outcome.

the probability you land inside the bigger circle but outside smaller circle is

125.6/153.86 = 0.82

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Answer:

\sqrt(3)[cos((4\pi )/(45))+isin((4\pi )/(45))]

Step-by-step explanation:

The first one.

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2 years ago
I need help with 6,7,8,9,10 please
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7 0
3 years ago
What is the measure of ∠S ?
jeka94

Alright, lets get started.

We could use sine law to find the remaining angle.

\frac{sinA}{a} =  \frac{sinB}{b}

\frac{sinS}{63.6}  = \frac{sin64}{69.8}

Plugging the value of sin 64

\frac{sinS}{63.6} =  \frac{0.8987}{69.8}

\frac{sinS}{63.6} = 0.01287

Cross multiplying

sin S = 0.8189

Taking inverse on both side

S = sin^{-1}(0.8189)

S = 55° : Answer

Hope it will help :)



4 0
3 years ago
Read 2 more answers
Find m abc (2x) (5x+5)
Gemiola [76]
< ABD + > ABC = 180.....because these angles form a linear pair
2x + 5x + 5 = 180
7x + 5 = 180
7x = 180 - 5
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x = 175/7
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< ABC = 5x + 5......5(25) + 5 = 130 <==
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3 years ago
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Solve the equation 6w2 – 7w – 20 = 0.
azamat

For this case we have the following quadratic equation:

6w ^ 2-7w-20 = 0

Where:

a = 6\\b = -7\\c = -20

Its roots will be given by:

w = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2 (a)}\\w = \frac {- (- 7) \pm \sqrt {(- 7) ^ 2-4 (6) (- 20)}} {2 (6)}\\w = \frac {7 \pm \sqrt {49 + 480}} {12}\\w = \frac {7 \pm \sqrt {529}} {12}\\w = \frac {7 \pm23} {12}

The roots are:

w_ {1} = \frac {7 + 23} {12} = \frac {30} {12} = \frac {15} {6} = \frac {5} {2}\\w_ {2} = \frac {7-23} {12} = \frac {-16} {12} = - \frac {8} {6} = - \frac {4} {3}

Answer:

w_ {1} = \frac {5} {2}\\w_ {2} = - \frac {4} {3}

7 0
3 years ago
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