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2 years ago

12

Please answer correctly !!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!!!!

1 answer:

sattari [20]2 years ago

7 0

Answer:

7.2 units

Step-by-step explanation:

$d=\sqrt{(x_{2}-x_{1})^2 + (y_{2}- y_{1})^2 } \\d= \sqrt{(-4+8)^2 + (-5-1)^2} \\d= \sqrt{4^2 + (-6)^2} \\d=\sqrt{16+36} \\d=\sqrt{52} \\d=7.22$

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Rite an algebraic expression to represent "five plus the quotient of r and 14."

hichkok12 [17]

The answer is 3) 5+r/14

Let's go segment by segment:
<span>"five plus" means addition, so we have 5 +

</span><span>"the quotient of r and 14" is the division result, so sign / must be present: 14/r
</span>
Therefore "five plus the quotient of r and 14" is 5 + 14/r

4 0

3 years ago

Mary is making pillows for her Life Skill class. She bought 2 ½ yards of fabric. Her total cost was $15. What was the cost per y

BigorU [14]

Answer:

15 divided by 2 1/2

Step-by-step explanation:

$6 per yard.

4 0

3 years ago

Which represents the polynomial written in standard form? 4m – 2m4 – 6m2 + 9 9 + 4m + 2m4 – 6m2 2m4 – 6m2 – 4m + 9 9 – 6m2 + 4m

Alenkasestr [34]

Answer:

$- 2m^4 - 6m^2 + 4m + 9$

Step-by-step explanation:

Given

$4m - 2m^4 - 6m^2 + 9$

Required

Express in standard form

To do this, we simply reorder the terms of the polynomial in descending order of power.

So, we have:

$- 2m^4 - 6m^2 + 4m + 9$

4 0

3 years ago

Read 2 more answers

Ahmed drive his car 4 hours continuously as average 80 Km/hr .if his speed was 60 Km in the 1st hour, 90 Km in the 2nd hour and

nadezda [96]

Answer:

I would say 120 but that could be also be wrong but ill go with 120

7 0

2 years ago

The general form of an parabola is 2x2−12x−3y+12=0 .

Murljashka [212]

Answer:

The standard form of the parabola is $(x-3)^2=4*\frac{3}{8}(y+2)$

Step-by-step explanation:

The standard form of a parabola is

$(x-h)^2=4p(y-k)$ .

In order to convert $2x^2-12x-3y+12=0$ into the standard form, we first separate the variables:

$2x^2-12x+3y+12=0\\\\2x^2-12x+12=3y$

we now divided both sides by 2 to remove the coefficient from $2x^2$ and get:

$x^2-6x+6=\frac{3}{2}y$ .

We complete the square on the left side by adding 3 to both sides:

$x^2-6x+6+3=\frac{3}{2}y+3$

$x^2-6x+9=\frac{3}{2}y+3$

$(x-3)^2=\frac{3}{2}y+3$

now we bring the right side into the form $4p(y-k)$ by first multiplying the equation by $\frac{2}{3}$ :

$\frac{2}{3} *(x-3)^2=\frac{2}{3} *(\frac{3}{2}y+3)\\\\\frac{2}{3} *(x-3)^2=y+2$

and then we multiplying both sides by $\frac{3}{2}$ to get

$(x-3)^2=\frac{3}{2} (y+2)$ .

Here we see that

$4p=\frac{3}{2}$

$\therefore p=\frac{3}{8}$

Thus, finally we have the equation of the parabola in the standard form:

$\boxed{(x-3)^2=4*\frac{3}{8}(y+2)}$

5 0

3 years ago