Answer:
Yes, we can assume that the percent of female athletes graduating from the University of Colorado is less than 67%.
Step-by-step explanation:
We need to find p-value first:
z statistic = (p⁻ - p0) / √[p0 x (1 - p0) / n]
p⁻ = X / n = 21 / 38 = 0.5526316
the alternate hypothesis states that p-value must be under the normal curve, i.e. the percent of female athletes graduating remains at 67%
H1: p < 0.67
z = (0.5526316 - 0.67) / √[0.67 x (1 - 0.67) / 38] = -0.1173684 / 0.076278575
z = -1.538681
using a p-value calculator for z = -1.538681, confidence level of 5%
p-value = .062024, not significant
Since p-value is not significant, we must reject the alternate hypothesis and retain the null hypothesis.
1 hour has 60 minutes.
Divide miles per hour by 60 to get miles per minute:
200 / 60 = 3.33 ( 3 1/3 ) miles per minute.
Answer:
8000000
Step-by-step explanation:
Option A:
V = 1/3 * b^2 * h
V = 1/3 * 10.5^2 * 6
V = 1/3 * 110.25 * 6
V = 220.5
Option B:
V = 1/3 * b^2 * h
V = 1/3 * 3.6^2 * 8
V = 1/3 * 12.96 * 8
V = 34.56
Option C:
V = 1/3 * b^2 * h
V = 1/3 * 4.2^2 * 12
V = 1/3 * 17.64 * 12
V = 70.56
Option D:
V = 1/3 * b^2 * h
V = 1/3 * 6^2 * 8.4
V = 1/3 * 36 * 8.4
V = 100.8
I guess it's 'None of the Above'
<span>3x^2 + 16x + 9 −16x − 12
= 3x^2 - 3
hope it helps</span>
