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AnnZ [28]
3 years ago
11

PLEASE help! Functions problem!

Mathematics
1 answer:
bezimeni [28]3 years ago
6 0

Answer:

C

Step-by-step explanation:

x = -1 and -7

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If f(x)=-x^2 and g(x) = -x^2+4x+5 what is the product
Dimas [21]

Answer:

x^{4} - 4x³ - 5x²

Step-by-step explanation:

-x²(-x² + 4x + 5)         Distribute

x^{4} - 4x³ - 5x²

If this answer is correct, please make me Brainliest!

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3 years ago
20 grams is 60% of what weight
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The height of a cylinder is 13centimeters. The volume of the cylinder is 16,328 cubic centimeters. What is the radius of the cyl
RUDIKE [14]

Answer: radius = 19.99 centimeters

Step-by-step explanation:

The formula for determining the volume of a cylinder is expressed as

Volume = πr²h

Where

r represents the radius of the cylinder.

h represents the height of the cylinder.

π is a constant whose value is 22/7

From the information given,

Volume = 16328 cubic centimeters

Height = 13 centimeters

Therefore,

16328 = 22/7 × r² × 13

16328 = 40.857r²

Dividing the left hand side and the right hand side of the equation by 40.857, it becomes

r² = 16328/40.857 = 399.6378

Taking square root of the left hand side and the right hand side of the equation, it becomes

r = 19.99 centimeters

7 0
3 years ago
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Is 3pi/2pi a rational number or an irrational number? Explain your reasoning
Vadim26 [7]

Answer:

It is rational

Step-by-step explanation:

The pi terms cancel out when you divide. This is due to the rule x/x = 1 where x is any number you want except x cannot be zero. So replace x with pi and we have pi/pi = 1

Therefore,

(3pi)/(2pi) = (3/2)*(pi/pi)

(3pi)/(2pi) = (3/2)*1 .... use the rule mentioned above

(3pi)/(2pi) = 3/2

we get a fraction or a ratio of two whole numbers, so this proves that the given expression is rational.

7 0
3 years ago
The weight of a product is normally distributed with a mean of four ounces and a variance of .25 "squared ounces." The company w
pychu [463]

Answer:

Weight=2.835

Step-by-step explanation:

See the attached picture for explanation.

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3 years ago
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