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3 years ago

10×+2=7 what is equal to 2x?

2 answers:

3 0

$x in (-oo:+oo)

2/7 = 2*x // - 2*x

2/7-(2*x) = 0

2/7-2*x = 0

2/7-2*x = 0 // - 2/7

-2*x = -2/7 // : -2

x = -2/7/(-2)

x = 1/7

x = 1/7$

guapka [62]3 years ago

3 0

2X=1 because you subtract 2 from each side to isolate x, and then you get 10x=5. Then divide 5 by 10, which leaves you with x=1/2, so you multiply that by 2 to solve for 2X, which is 1

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Mr. Brown shares with the class that 70% of the students got an A on the English vocabulary quiz. If Mr. Brown has 100 students,

mezya [45]

Answer:

a. $\frac{70}{100}$

b. 0.7

c. 0.7=70%= $\frac{70}{100}$

Step-by-step explanation:

70% of 100 received an A, that is 70/100 times 100 equal to 70

$\frac{70}{100}*100=70$

a. 70% = $\frac{70}{100}$

b. $\frac{70}{100}$ = 0.7

Notice that 70/100 is equal to 7/10 which is 0.7

c. 0.7=70%= $\frac{70}{100}$

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3 years ago

The graph of a linear function is shown.

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Answer:

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3 years ago

Find ten rational numbers between -1 by 5 and 1 by 2

uysha [10]

Answer:

Step-by-step explanation:

First both the rational numbers should have same denominators. So, find least common denominator

Least common denominator is 10

$\frac{-1}{5}=\frac{-1*2}{5*2}=\frac{-2}{10}\\\\\\\frac{1}{2}=\frac{1*5}{2*5}=\frac{5}{10}\\\\\\$

Now multiply the numerator and denominators of the both the numbers by 10.

$\frac{-2*10}{10*10}= \frac{-20}{100} \ and \ \frac{5*10}{10*10}=\frac{50}{100}\\\\\\Now\ 10 \ rational \ numbers \ between\frac{-20}{10} \ and \ \frac{50}{100} \ is \\\\\\\frac{-19}{100},\frac{-18}{100},\frac{-17}{100},\frac{-16}{100}.\frac{-15}{100},\frac{-14}{100},\frac{-13}{100},\frac{-12}{100},\frac{-11}{100};\frac{-10}{100}$

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3 years ago

The Eco Pulse survey from the marketing communications firm Shelton Group asked individuals to indicate things they do that make

Bad White [126]

Answer:

a) There is a probability of 42% that the person will feel guilty for only one of those things.

b)There is a probability of 46% that a randomly selected person will not feel guilty for either of these reasons

Step-by-step explanation:

This probability problem can be solved by building a Venn like diagram for each probability.

I say that we have two sets:

-Set A, for those people that will feel guilty about wasting food.

-Set B, for those people that will feel guilty about leaving lights on when not in a room.

The most important information is that there is a .12 probability that a randomly selected person will feel guilty for both of these reasons. It means that $P(A \cap B) = .12.$

The problem also states that there is a .39 probability that a randomly selected person will feel guilty about wasting food. It means that P(A) = 0.39. The probability of a person feeling guilty for only wasting food is PO(A) = .39-.12 = .27.

Also, there is a .27 probability that a randomly selected person will feel guilty about leaving lights on when not in a room. So, the probability of a person feeling guilty for only leaving the lights on is PO(B) = 0.27-0.12 = 0.15.

a) What is the probability that a randomly selected person will feel guilty for either wasting food or leaving lights on when not in a room?

This is the probability that the person feels guilt for only one of those things, so:

P = PO(A) + PO(B) = 0.27 + 0.15 = 0.42 = 42%

b) What is the probability that a randomly selected person will not feel guilty for either of these reasons

The sum of all the probabilities is always 1. In this problem, we have the following probabilies

- The person will not feel guilty for either of these reasons: P

- The person will feel guilty for only one of those things: PO(A) + PO(B) = 0.42

- The person will feel guilty for both reasons: PB = 0.12

`P + 0.42 + 0.12 = 1

P = 1-0.54

P = 0.46

There is a probability of 46% that a randomly selected person will not feel guilty for either of these reasons

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3 years ago

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Kaylis [27]

12 would be considered a natural number, whole number, and an integer
Hope this helped

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3 years ago