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cestrela7 [59]
3 years ago
13

10×+2=7 what is equal to 2x?

Mathematics
2 answers:
lakkis [162]3 years ago
3 0
x in (-oo:+oo)

2/7 = 2*x // - 2*x

2/7-(2*x) = 0

2/7-2*x = 0

2/7-2*x = 0 // - 2/7

-2*x = -2/7 // : -2

x = -2/7/(-2)

x = 1/7

x = 1/7
guapka [62]3 years ago
3 0
2X=1 because you subtract 2 from each side to isolate x, and then you get 10x=5. Then divide 5 by 10, which leaves you with x=1/2, so you multiply that by 2 to solve for 2X, which is 1
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3 years ago
A. 6x^3+18x<br> b.6x^2+3<br> c.36x^2+18<br> d. 36x^2+3
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3 years ago
Determine the singular points of the given differential equation. Classify each singular point as regular or irregular. (Enter y
ludmilkaskok [199]

Answer:

Step-by-step explanation:

Given that:

The differential equation; (x^2-4)^2y'' + (x + 2)y' + 7y = 0

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y'' + \dfrac{(x+2)}{(x^2-4)^2} \ y'+ \dfrac{7}{(x^2- 4)^2} \ y=0

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This implies that:

p(x) = \dfrac{(x+2)}{(x^2-4)^2} \

p(x) = \dfrac{(x+2)}{(x+2)^2 (x-2)^2} \

p(x) = \dfrac{1}{(x+2)(x-2)^2}

Also;

q(x) = \dfrac{7}{(x^2-4)^2}

q(x) = \dfrac{7}{(x+2)^2(x-2)^2}

From p(x) and q(x); we will realize that the zeroes of (x+2)(x-2)² = ±2

When x = - 2

\lim \limits_{x \to-2} (x+ 2) p(x) =  \lim \limits_{x \to2} (x+ 2) \dfrac{1}{(x+2)(x-2)^2}

\implies  \lim \limits_{x \to2}  \dfrac{1}{(x-2)^2}

\implies \dfrac{1}{16}

\lim \limits_{x \to-2} (x+ 2)^2 q(x) =  \lim \limits_{x \to2} (x+ 2)^2 \dfrac{7}{(x+2)^2(x-2)^2}

\implies  \lim \limits_{x \to2}  \dfrac{7}{(x-2)^2}

\implies \dfrac{7}{16}

Hence, one (1) of them is non-analytical at x = 2.

Thus, x = 2 is an irregular singular point.

5 0
3 years ago
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MAXImum [283]

Answer:

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Step-by-step explanation:

i hope this helped :)

4 0
3 years ago
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The average of 3,5,10 and X is 6, what is the value of X?
Rashid [163]
x = 6
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18 + x = 24, subtract 18 from 24 to get x = 6.
6 0
3 years ago
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