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Burka [1]
3 years ago
10

An eight-sided die is rolled and a coin is tossed. What is the probability of landing on an even number and getting heads?

Mathematics
1 answer:
Alik [6]3 years ago
5 0

Answer: 4/8 for even number and 1/2 for landing on heads

Step-by-step explanation: only 4 even numbers out of 8 from 1-8 and only 2 sides on coin

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In the figure shown, r || s. If the measure of ∠ 2 = 146°, what is the measure of ∠ 7
borishaifa [10]

Answer:

34°

Step-by-step explanation:

1. First, let's find the measure of ∠1 because since r || s, that means ∠1 = ∠7 because they're both alternate exterior angles. Alternate exterior angles are congruent.

2. (Solving for ∠1)

  • 146 + x = 180
  • 146 + x - 146 = 180 - 146
  • x = 34

3. Now, since we know ∠1 = ∠7, ∠7 = 34°.

3 0
2 years ago
(-4,5) and (4,0) find the distance between each pair of points
aleksklad [387]

Answer:

9.4339 units

Step-by-step explanation:

Here we are given with two coordinates and asked to determine the distance between them.

Here we are going to use the distance formula, which is given as under

D=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}

Where

(x_1,y_1) = (-4,5)

(x_2,y_2) = (4,0)

Replacing these values in the distance formula

D =\sqrt{(-4-4))^2+(5-0)^2}

D =\sqrt{(-8)^2+(5)^2}

D =\sqrt{64+25}

D =\sqrt{89}

D= 9.4339

Hence the distance is 9.4339 units

6 0
3 years ago
Please help i don't even where to start<br><br>solve for x​
aliina [53]

The radius is 10, so the diameter is 20. This means the parts of the diameter (the chord through the center P) to the left and right of the vertical chord have lengths 16 and 4, respectively.

Because the horizontal chord is a diameter, the vertical chord is cut in half, so its parts above and below the diameter both have length <em>x</em>.

Now, by the intersecting chord theorem,

16×4 = <em>x</em> × <em>x</em>

or

<em>x</em> ² = 64

so that

<em>x</em> = 8

6 0
3 years ago
Find the measure of each interior angle of the regular polygon
jek_recluse [69]
I believe 60 degree is your answer
4 0
3 years ago
Read 2 more answers
The center of the inscribed circle of Triangle ABC is point , and the center of the circumscribed circle of Triagnle ABC is poin
quester [9]

Answer:

Part A: The center of The inscribed circle is the point S

Part B: The center of The circumscribed circle is the point P

Step-by-step explanation:

Part A: Find the center of The inscribed circle of ΔABC

The inscribed circle will touch each of the three sides of the triangle in exactly one point,

The center of the inscribed circle is the point of intersection between the angle bisectors of the triangle.

<u>So, </u>According to the previous definition:

A₁A₂ and B₁B₂ are the angle bisectors of ∠A and ∠B

So, the inter section between them is the center of <u>The inscribed circle</u>

<u>So, the center of The inscribed circle is the point S</u>

=====================================================

Part B: Find the center of The circumscribed circle of ΔABC

The circumscribed circle is the circle that passes through all three vertices of the triangle.

The center of the circumscribed circle is the point of intersection between the perpendicular bisectors of the sides.

<u>So,</u> According to the previous definition:

P₁P₂ and Q₁Q₂ are the perpendicular bisectors of AB and BC

So, the inter section between them is the center of <u>The circumscribed circle</u>

<u>So, the center of The circumscribed circle is the point P</u>

5 0
3 years ago
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