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Nutka1998 [239]
3 years ago
6

I need help with the grape.

Mathematics
1 answer:
Natalka [10]3 years ago
4 0
This is the graph, on the x and y axis od the graph you plot the point at 4 (positive)

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Order these decimals from smallest to largest 1.89 -0.81 -2.6 0.24 -1.7
tiny-mole [99]

Answer:

-2.6, -1.7, -0.81, 0.24, 1.89

Step-by-step explanation:

5 0
3 years ago
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Drag the expressions into the boxes to correctly complete the table.
lora16 [44]

Answer:

SUMMARY:

x^4+\frac{5}{x^3}-\sqrt{x}+8                               →    Not a Polynomial

-x^5+7x-\frac{1}{2}x^2+9                           →    A Polynomial

x^4+x^3\sqrt{7}+2x^2-\frac{\sqrt{3}}{2}x+\pi              →    A Polynomial

\left|x\right|^2+4\sqrt{x}-2                                   →    Not a Polynomial

x^3-4x-3                                        →    A Polynomial

\frac{4}{x^2-4x+3}                                              →    Not a Polynomial

Step-by-step explanation:

The algebraic expressions are said to be the polynomials in one variable which consist of terms in the form ax^n.

Here:

n = non-negative integer

a = is a real number (also the the coefficient of the term).

Lets check whether the Algebraic Expression are polynomials or not.

Given the expression

x^4+\frac{5}{x^3}-\sqrt{x}+8

If an algebraic expression contains a radical in it then it isn’t a polynomial. In the given algebraic expression contains \sqrt{x}, so it is not a polynomial.

Also it contains the term \frac{5}{x^3} which can be written as 5x^{-3}, meaning this algebraic expression really has a negative exponent in it which is not allowed. Therefore, the expression x^4+\frac{5}{x^3}-\sqrt{x}+8 is not a polynomial.

Given the expression

-x^5+7x-\frac{1}{2}x^2+9

This algebraic expression is a polynomial. The degree of a polynomial in one variable is considered to be the largest power in the polynomial. Therefore, the algebraic expression is a polynomial is a polynomial with degree 5.

Given the expression

x^4+x^3\sqrt{7}+2x^2-\frac{\sqrt{3}}{2}x+\pi

in a polynomial with a degree 4. Notice, the coefficient of the term can be in radical. No issue!

Given the expression

\left|x\right|^2+4\sqrt{x}-2

is not a polynomial because algebraic expression contains a radical in it.

Given the expression

x^3-4x-3

a polynomial with a degree 3. As it does not violate any condition as mentioned above.

Given the expression

\frac{4}{x^2-4x+3}

\mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}

Therefore, is not a polynomial because algebraic expression really has a negative exponent in it which is not allowed.

SUMMARY:

x^4+\frac{5}{x^3}-\sqrt{x}+8                               →    Not a Polynomial

-x^5+7x-\frac{1}{2}x^2+9                           →    A Polynomial

x^4+x^3\sqrt{7}+2x^2-\frac{\sqrt{3}}{2}x+\pi              →    A Polynomial

\left|x\right|^2+4\sqrt{x}-2                                   →    Not a Polynomial

x^3-4x-3                                        →    A Polynomial

\frac{4}{x^2-4x+3}                                              →    Not a Polynomial

3 0
3 years ago
Thang decided to borrow ​$7000 from his local bank to help pay for a car. His loan was for 3 years at a simple interest rate of
jekas [21]
You need to find 24% of $7000 because that's the total interest over the course of 3 years. The answer is $1680

6 0
3 years ago
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I’ve been missing school a lot for personal reasons,can i get help with this one ?
Alecsey [184]

Step-by-step explanation:

boom therrs tha answer

4 0
3 years ago
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Danielle estimates that she will spend $250 on new summer clothes. She actually spent $350. What is the percent error? Round to
lesya [120]

Answer:

%28.57 (14285714286)

Step-by-step explanation:

Divid To get decimal (percent right)

250/350= 0.714285714285714

Subtract from 1 to get decimal (Percent wrong)

1.0 - 0.714285714285714= 0.285714285714286

Move over decimal to placements to the right to convert to percent

%28.5714285714286

Round

%28.57

8 0
3 years ago
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