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seropon [69]
3 years ago
13

I need help with system of equations. {y=2x - 6 {4x - 2y = 14

Mathematics
2 answers:
Phantasy [73]3 years ago
6 0
Hope this helps you.

Lera25 [3.4K]3 years ago
3 0
Resolving by the substitution method:
\left \{ {{y=2x-6\:(I)} \atop {4x-2y=14\:(II)}} \right.

Replace the value of "Y" in the second equation:
4x-2y=14\:(II)
4x - 2*(2x-6) = 14
4x - 4x + 12 = 14
0x = 14 - 12
\boxed{\boxed{0x = 2 \: (\nexists)}}\end{array}}\qquad\quad\checkmark

or

\left \{ {{y=2x-6\:(I)} \atop {4x-2y=14\:(II)}} \right.
\left \{ {{-2x+y=-6\:*(2)} \atop {4x-2y=14\:\:\:\:\:\:}} \right.

\left \{ {{-\diagup\!\!\!\!4x+\diagup\!\!\!\!2y=-12} \atop {\diagup\!\!\!\!4x-\diagup\!\!\!\!2y=14}} \right.
\boxed{\boxed{0 = 2 \: (\nexists)}}\end{array}}\qquad\quad\checkmark

Answer:
\underline{No\:solutions (Undetermined)}
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Step-by-step explanation:

For this case we have the following function:

h(t) = -6.3t^2 +53 t+24

In order to maximize this function we need to take the first derivate respect the time and we have:

h'(t) = -12.6 t +53

Now we can set up the derivate equal to 0 and we have:

-12.6 t +53 = 0

And solving for t we got:

t = \frac{53}{12.6}= 4.206

For the second derivate respect the time we got:

h''(t) = -12.6

So then we can conclude that t = 4.206 is a maximum for the function.

And the corresponding height would be:

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