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Ivanshal [37]
3 years ago
6

Lena needs $50 to buy some notebooks. She had saved $2 and plans to work as a babysitter to earn $8 per hour.

Mathematics
1 answer:
____ [38]3 years ago
8 0
<span>2 + 8n ≤ 50, so n ≤ 6 </span>
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Each of the walls of a room with square dimensions has been built with two pieces of sheetrock, a smaller one and a larger one.
azamat
To solve this problem you must apply the proccedure shown below:

 1. You have the following information given in the problem above:

 -  The<span> room has square dimensions and it has been built with two pieces of sheetrock, a smaller one and a larger one.

 2. Therefore, let's call

 x: the smaller one.
 y: the larger one.

 3. Then, you have that the lenght of the wall is the sum of the smaller one and the larger one:

 x+y

 4. So, the area of the room is:

 (x+y)(x+y)
 (x+y)</span>²

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8 0
3 years ago
Jin can purchase 10 gallons of biodegradable fuel for $42.99 at the local
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Answer:

b 15 gallons of fuel for $60.50

Step-by-step explanation:

because 1 gallon of fuel is for $4.299

and when you multiply 15×4.299 the answer is 64.485 which is greater than the offer you are getting it for.

3 0
2 years ago
What is one more than -5
Cerrena [4.2K]
All real numbers above -4
3 0
3 years ago
Read 2 more answers
Simplify the expression 4x^3/28x^4
KIM [24]
1/7x

Factorize the numbers (4 and 28) as they have a common factor of 4 so you can simplify it to 1/7. Cancel out the 3 in the x (numerator) from the denominator and you will have x^1 remaining in the denominator. That is also the same as x, therefore making it 1/(7x)
5 0
2 years ago
Find y as a function of x if y"' + 9y' = 0, y(0) = 6, y'(0) = 9, y"(0) = 18. y(x) =
Andreas93 [3]

Answer:

y(x) = 8 - 2cos 3x + 3sin 3x

Step-by-step explanation:

Given the equation:

y''' + 9y' = 0

The characteristic equation :

⇒r³ + 9r =0

Solving for r, we get r = 0 and r = ± 3i

The general equation for such equation is :

<u>y = C₁ + C₂cos 3x + C₃sin 3x</u>

Given:

y(0) = 6

Thus, Applying in the above equation, we get

<u>6 = C₁ + C₂ .......................................................1</u>

Differentiating y , we get:

<u>y' = -3C₂sin 3x + 3C₃cos 3x</u>

Given:

y'(0) = 9

Thus, Applying in the above equation, we get

<u>9 = 3C</u><u>₃</u>

or,

<u>C</u><u>₃</u><u> = 3</u>

Differentiating y' , we get:

<u>y'' = -9C₂cos 3x - 9C₃sin 3x</u>

Given:

y''(0) = 18

Thus, Applying in the above equation, we get

<u>18 = -9C</u><u>₂</u>

or,

<u>C</u><u>₂</u><u> = -2</u>

Applying in equation 1 , we get:

<u>C₁ = 8</u>

Thus,

<u>y(x) = 8 - 2cos 3x + 3sin 3x</u>

4 0
3 years ago
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