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drek231 [11]
4 years ago
11

Which type of scientific statement describes a proven fact about how things function in nature? a law a theory an inquiry a hypo

thesis
Physics
2 answers:
WITCHER [35]4 years ago
8 0

Which type of scientific statement describes a proven fact about how things function in nature? a law a theory an inquiry a hypothesis

The key word is "proven fact". The answer is: a law.

babymother [125]4 years ago
4 0
<h3><u>Answer;</u></h3>

Law

<u>A Law </u>is type of scientific statement that describes a proven fact about how things function in nature.

<h3><u>Explanation;</u></h3>
  • Scientific theory is an explanation of observations supported by many tests and accepted by a general consensus of scientists.
  • <em><u>A scientific Law describes a pattern that occurs in nature or in other words observed phenomenon.</u></em>
  • Therefore; a scientific theory is an explanation based on many observations during many repeated experiments while, a scientific law is a rule that describes the behavior of something in nature.
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A conventional current of 8 A runs clockwise in a circular loop of wire in the plane, with center at the origin and with radius
alisha [4.7K]

Answer:

I2 = 3.076 A

Explanation:

In order to calculate the current in the second loop, you take into account that the magnitude of the magnetic field at the center of the ring is given by the following formula:

B=\frac{\mu_oI}{2R}        (1)

I: current in the wire

R: radius of the wire

μo: magnetic permeability of vacuum = 4π*10^-7 T/A

In the case of the two wires with opposite currents and different radius, but in the same plane, you have that the magnitude of the magnetic field at the center of the rings is:

B_T=\frac{\mu_oI_1}{2R_1}-\frac{\mu_oI_2}{2R_2}         (2)

I1: current of the first ring = 8A

R1: radius of the first ring = 0.078m

I2: current of the second ring = ?

R2: radius of the first second = 0.03m

To find the values of the current of the second ring, which makes the magnitude of the magnetic field equal to zero, you solve the equation (2) for I2:

\frac{\mu_oI_2}{2R_2}=\frac{\mu_oI_1}{2R_1}\\\\I_2=I_1\frac{R_2}{R_1}=(8A)\frac{0.03m}{0.078m}=3.076A

The current of the second ring is 3.076A and makes that the magntiude of the total magnetic field generated for both rings is equal to zero.

5 0
3 years ago
If y=5sin (3x -40)<br>Calculate the frequency and period​
ioda

Answer:

0.477 Hz

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Explanation:

y = A sin(ωx − φ)

A is the amplitude, ω is the angular frequency, and φ is the phase shift.

ω = 3 rad/s

f = ω / 2π ≈ 0.477 Hz

T = 1/f ≈ 2.09 s

8 0
3 years ago
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