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3 years ago

Can a body have constant speed and still be acclerating ? Give an Example

Physics

1 answer:

Allushta [10]3 years ago

3 0

Hi Pupil Here's Your answer :::

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An object moving with constant speed can be accelerated if direction of motion changes. For example, an object moving with a constant speed in a circular path has an acceleration because its direction of motion changes continuously.

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Hope this Helps . . . . . . . . .

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The equation for the speed of a satellite in a circular orbit around the earth depends on mass. Which mass?

katovenus [111]

<h3><u>Question: </u></h3>

The equation for the speed of a satellite in a circular orbit around the Earth depends on mass. Which mass?

a. The mass of the sun

b. The mass of the satellite

c. The mass of the Earth

<h3><u>Answer:</u></h3>

The equation for the speed of a satellite orbiting in a circular path around the earth depends upon the mass of Earth.

Option c

<h3><u> Explanation: </u></h3>

Any particular body performing circular motion has a centripetal force in picture. In this case of a satellite revolving in a circular orbit around the earth, the necessary centripetal force is provided by the gravitational force between the satellite and earth. Hence $F_{G} = F_{C}$ .

Gravitational force between Earth and Satellite: $F_{G} = \frac{G \times M_e \times M_s}{R^2}$

Centripetal force of Satellite : $F_C = \frac{M_s \times V^2}{R}$

Where G = Gravitational Constant

$M_e$ = Mass of Earth

$M_s$ = Mass of satellite

R= Radius of satellite’s circular orbit

V = Speed of satellite

Equating $F_G = F_C$ , we get

Speed of Satellite $V =\frac{\sqrt{G \times M_e}}{R}$

Thus the speed of satellite depends only on the mass of Earth.

6 0

3 years ago

supose at 20 degree celsius the resistance of Tungsten thermometer is 154.9. WHen placed in a particular solution , the resistan

saw5 [17]

Answer:

T₂ = 95.56°C

Explanation:

The final resistance of a material after being heated is given by the relation:

R' = R(1 + αΔT)

where,

R' = Final Resistance = 207.4 Ω

R = Initial Resistance = 154.9 Ω

α = Temperature Coefficient of Resistance of Tungsten = 0.0045 °C⁻¹

ΔT = Change in Temperature = ?

Therefore,

207.4 Ω = 154.9 Ω[1 + (0.0045°C⁻¹)ΔT]

207.4 Ω/154.9 Ω = 1 + (0.0045°C⁻¹)ΔT

1.34 - 1 = (0.0045°C⁻¹)ΔT

ΔT = 0.34/0.0045°C⁻¹

ΔT = 75.56°C

but,

ΔT = Final Temperature - Initial Temperature

ΔT = T₂ - T₁ = T₂ - 20°C

T₂ - 20°C = 75.56°C

T₂ = 75.56°C + 20°C

7 0

3 years ago

A quartz crystal vibrates with a frequency of 93621 Hz. What is the period of the crystals motion? T=1/93621 does not give me th

hram777 [196]

Answer:0.0000107s

Explanation:

f=1/T

T=1/f

f=93621 1/s

t=1/93621

T=0.00001068 s

3 0

3 years ago

if two point charges are separated by 1.5 cm and have charge values of 2.0 and -4.0, respectively, what is the value of the mutu

RUDIKE [14]

Complete question:

if two point charges are separated by 1.5 cm and have charge values of +2.0 and -4.0 μC, respectively, what is the value of the mutual force between them.

Answer:

The mutual force between the two point charges is 319.64 N

Explanation:

Given;

distance between the two point charges, r = 1.5 cm = 1.5 x 10⁻² m

value of the charges, q₁ and q₂ = 2 μC and - μ4 C

Apply Coulomb's law;

$F = \frac{k|q_1||q_2|}{r^2}$

where;

F is the force of attraction between the two charges

|q₁| and |q₂| are the magnitude of the two charges

r is the distance between the two charges

k is Coulomb's constant = 8.99 x 10⁹ Nm²/C²

$F = \frac{k|q_1||q_2|}{r^2} \\\\F = \frac{8.99*10^9 *4*10^{-6}*2*10^{-6}}{(1.5*10^{-2})^2} \\\\F = 319.64 \ N$

Therefore, the mutual force between the two point charges is 319.64 N

4 0

3 years ago

Peak to peak value of voltage is

hram777 [196]

Answer: Peak-to-peak voltage is the distance from the lowest negative amplitude, or trough, to the highest positive amplitude, or crest, of the AC voltage waveform. In other words, peak-to-peak voltage is equal to the full height of the waveform. Peak-to-peak voltage can be found using peak voltage or RMS voltage.

Explanation:hope tht gave u a clue have a wonderful Christmas Eve time with your family!❄️

3 0

2 years ago

Read 2 more answers