Ask question

Ask question

All categories

2 years ago

8

What is 7.832 rounded to the nearest 10th?

1 answer:

Galina-37 [17]2 years ago

3 0

When rounding you look at the number right after the one you want to round. The tenth place is the one right after the decimal. If the number after it is more than five it goes up by one, it it's less than five it stays the same. So since the number after the 8 is a 3 it stays the same.

The answer is 7.8

You might be interested in

What is formed when the rock making up a tectonic plate breaks and moves Select one of the options below as your answer:

dem82 [27]

A. a fault hopes this helps you guys

6 0

3 years ago

The frequency of the given sound is 1.5khz then how many vibration it is completing in one second ?

kompoz [17]

Answer:

1500 per second.

Explanation:

vibrations = 1.5 kilohertz

1.5×1000=1500

the answer is 1500 per second.

6 0

2 years ago

Read 2 more answers

What is short circuit

Marizza181 [45]

Answer:

A short circuit is an electrical circuit that allows

Explanation:

3 0

3 years ago

Read 2 more answers

A wedge shaped air film is made between two sheets of glass using a spacer at one end of the glass sheets. If light of wavelengt

pychu [463]

Answer:

1178 nm

Explanation:

We are given that

Wavelength of light= $\lambda=589nm=589\times 10^{-9} m$

$1nm=10^{-9} m$

We have to find the thickness of spacer if five dark fringes are observed between the edges of the glass.

Suppose that first dark fringe and fifth dark fringe near spacer, then the path length of light is 4 times the wavelength of light.

The light passes through air film is two times then the change in air film thickness from one edge to other is two times the wavelength of light.

Change in air film thickness from one edge to other edge is same as the thickness of spacer.

Therefore, thickness of spacer= $2\lambda$

Thickness of spacer= $2\times 589\times 10^{-9}$ m

Thickness of spacer=1178 nm

Hence, the thickness of spacer=1178 nm

8 0

2 years ago

Marisa’s car accelerates at an average rate of 2.6m/s^2. Calculate how long it takes her car to accelerate from 24.6m/s to 26.8m

djverab [1.8K]

given info is... Acceleration(a)=2.6m/s^2

final velocity(v)=26.8m/s

initial velocity(u)=24.6m/s

need to find.... time(t)=?

$a=\frac{v-u}{t} \\2.6=\frac{26.8-24.6}{t} \\\\$

$t=\frac{v-u}{a}$

$t=\frac{26.8-24.6}{2.6}$

$t=0.846s$

Explanation:

8 0

3 years ago