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Anuta_ua [19.1K]
3 years ago
7

Anyone want to help me out?

Mathematics
1 answer:
Artemon [7]3 years ago
8 0

Answer:

SAS Postulate (third option)

Step-by-step explanation:

A trick that I use is that s stands for side and a for angle

the picture shows that two sides are the same which means the SS

and one angle is the same, hence the one A

Hope this helps!

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The table below represents the distance of a train from its destination as a function of time: Time (hours) x Distance (miles) y
stiv31 [10]
A.  y=-95x+665  y-intercept is 665
B.  Ave rate of change is -95
C.  y=0 so x=7 Domain is [0,7]
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ANSWER ASAP PLEASE IM BEING TIMED I WILL GIVE BRAINLIESTTTT
stiv31 [10]

Answer:

3 y ( 2 x − 1 ) ( x − 4 y )

Step-by-step explanation:

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Carly beat the school record for the 400 meter run by 1.3 seconds. if she ran the race in 55.7 seconds, what was the record
sp2606 [1]
If Carly broke the record by 1.3 seconds and Carly's time was 55.7 the old record would be Carly's time plus 1.3 seconds for the time that Carly broke the record by, so... 57 seconds was the old record
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Delia drives 220 km in 2 hours. Calculate her average speed in km/hrs.
alexira [117]
110 because avg speed is total distance over total time
8 0
2 years ago
Find the distance from the point (1,4) to the line y = 1/3x - 3
Troyanec [42]

Answer:

Step-by-step explanation:

If I'm not mistaken, and I very well could be, this is a calculus problem(?). In order to find the distance without calculus you'd need a point on the given line to use to find the distance in the distance formula. But you don't have a point on the given line, so we can find the shortest distance between the point (1, 4) and the given line using the derivative of the polynomial formed when using the distance formula.

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} and we have the x and y for x2 (or x1...it doesn't matter which you choose to fill in):

d=\sqrt{(1-x)^2+(4-y)^2}

but what we find is that we have too many unknowns here, namely, the distance, the x coordinate, and the y coordinate. So we can replace the y coordinate with what y is equal to in terms of the linear equation:

d=\sqrt{(1-x)^2+(4-\frac{1}{3}x-3)^2 } and simplify:

d=\sqrt{(1-x)^2+(7-\frac{1}{3}x)^2 }

. No we'll expand each binomial by squaring:

d=\sqrt{(1-2x+x^2)+(49-\frac{14}{3}x+\frac{1}{9}x^2)  }

.  Combining like terms gives us

d=\sqrt{\frac{10}{9}x^2-\frac{20}{3}x+50  }

The distance between the point (1, 4) and the given line will be at a minimum when the polynomial above is at a minimum. We find the value of x for which the polynomial is at a minimum by finding its derivative, setting the derivative equal to 0, and then solving for x. The derivative of the polynomial is

\frac{20}{9}x-\frac{20}{3}

Setting equal to 0 and getting rid of the denominators gives us

20x - 60 = 0

Solving for x gives us

20x = 60 and x = 3.

That's the value of x that gives us the shortest distance between (1, 4) and the line y = 1/3x - 3. Sub into the distance formula that x value to find the distance:

d=\sqrt{(\frac{10}{9})(3)^2-(\frac{20}{3})(3)+50   }

which simplifies down, finally, to

x ≈ 6.325 units

8 0
2 years ago
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