Ask question

Ask question

All categories

1 year ago

12

Find the value of X.

1 answer:

tatuchka [14]1 year ago

4 0

This is the correct answer

You might be interested in

Firdavs [7]

M(p) = 5p-40 (apex) ....

7 0

3 years ago

Read 2 more answers

This graph represents the positions

sleet_krkn [62]

Answer:

step g

Step-by-step explanation:

it axis is giong up more than other turtle which makes more sense.

for more homework awnser follow me on instagram ad dm me.

its.emma.sloan

4 0

3 years ago

A plane flew 187 miles from new York to Boston Massachusetts it then few 273 miles from B

USPshnik [31]

187+273=460 total miles of flight

4 0

3 years ago

Read 2 more answers

If A and B are two independent events with P(A)=2÷3 and P(B) =1÷5, find P(AUB).

iren [92.7K]

Answer:

$for \: independent \: events : \\ P(AUB) = P(A) + P(B) \\ P(AUB) = \frac{2}{3} + \frac{1}{5} \\ = \frac{13}{15}$

Step-by-step explanation:

P(AUB) is P(A) + P(B) because P(AnB) is zero.

$P(AUB) = P(A) + P(B) - P(A{ \huge{n} }B) \\ P(AUB) = P(A) + P(B) + 0$

3 0

3 years ago

Find the general solution of the diﬀerential equation y^(5) −2y^(4) + y^(3) = 0.

Gwar [14]

$y^{(5)}-2y^{(4)}+y^{(3)}=0$

We can reduce the order of the ODE by substituting $v(x)=y^{(3)}(x)$ , so that $v'(x)=y^{(4)}(x)$ and $v''(x)=y^{(5)}(x)$ . Then

$v''-2v'+v=0$

has characteristic equation

$r^2-2r+1=(r-1)^2=0$

with root $r=1$ , which has multiplicity 2, so that the characteristic solution is

$v_c=C_1e^x+C_2xe^x$

Integrate both sides to solve for $y''(x)$ :

$y''=C_1e^x+C_2e^x(x-1)+C_3$

$y''=C_1e^x+C_2xe^x+C_3$

Integrate again to solve for $y'(x)$ :

$y'=C_1e^x+C_2e^x(x-1)+C_3x+C_4$

$y'=C_1e^x+C_2xe^x+C_3x+C_4$

And one last time to solve for $y(x)$ :

$y=C_1e^x+C_2e^x(x-1)+\dfrac{C_3}2x^2+C_4x+C_5$

$\boxed{y(x)=C_1e^x+C_2e^x+C_3x^2+C_4x+C_5}$

6 0

3 years ago