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Anon25 [30]
3 years ago
8

Divide using long division.

Formula1" title="(2x^{3} +5x^{2} -7x+6)" alt="(2x^{3} +5x^{2} -7x+6)" align="absmiddle" class="latex-formula"> ÷ (x^{2} +3x-4)
Mathematics
1 answer:
babunello [35]3 years ago
3 0

Answer:

The quotient = 2x - 1 and the remainder = 4x + 2

Step-by-step explanation:

\frac{2x^{3}+5x^{2}-7x+6}{x^{2}+3x-4}=2x+\frac{-x^{2}+x+6}{x^{2}+3x-4}

\frac{-x^{2}+x+6 }{x^{2}+3x-4}=-1+\frac{4x+2}{x^{2}+3x-4}

The quotient = 2x - 1 and the remainder = 4x + 2

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(7 4/9 −8)∙3.6–1.6∙( 1/8 − 3/4 )+1 2/5 ÷(−0.35)
lidiya [134]

Answer:

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Step-by-step explanation:

(7 4/9 −8)∙3.6–1.6∙( 1/8 − 3/4 )+1 2/5 ÷(−0.35)

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3 0
3 years ago
Which solution set is graft on the number line
vfiekz [6]

Answer:

x < 1

Step-by-step explanation:

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4 0
1 year ago
Read 2 more answers
Can anybody help this question?
Oxana [17]

Answer:

the first option

Step-by-step explanation:

really, just look at the table.

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I hope you can see right away that it is not.

and you can see they are not the same either.

so, all the answer options mentioning mean larger than median or equal to median can be ruled out right away.

so, it is between the first two options.

now think ! how do we draw number lines ? a coordinate axis ?

the smaller numbers left, the larger numbers right. the numbers grow from left to right.

the mean value is simply the sum of all measurements divided by the number of measurements (how many median were done). if that is smaller that the median (so, the Mean is left of the Median), it means that the majority of measurements had a result smaller (to the left) than the Median. so, it is skewed-left.

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3 years ago
8. Solve for x.<br> A 30<br> C 180<br> B 60<br> D 90
xxTIMURxx [149]

Answer:

<em><u> </u></em><em><u>Given </u></em><em><u>:</u></em>

<em><u>=</u></em><em><u>></u></em><em><u> </u></em><em><u>An </u></em><em><u>equilateral</u></em><em><u> Triangle</u></em><em><u> </u></em><em><u>i.e </u></em><em><u>a </u></em><em><u>triangle</u></em><em><u> </u></em><em><u>which </u></em><em><u>have </u></em><em><u>all </u></em><em><u>it's</u></em><em><u> </u></em><em><u>side </u></em><em><u>equal.</u></em>

<em><u>To </u></em><em><u>Find </u></em><em><u>:</u></em>

<em><u>=</u></em><em><u>></u></em><em><u>The </u></em><em><u>value </u></em><em><u>of </u></em><em><u>(</u></em><em><u>2</u></em><em><u>x</u></em><em><u>)</u></em><em><u>°</u></em>

<em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>-</u></em><em><u>❣️</u></em>

<h2><em><u>Solution</u></em><em><u> </u></em></h2>

<em><u>----_______----❣️</u></em>

<em><u>1</u></em><em><u>. </u></em><em>We </em><em>know</em><em> </em><em>that </em><em>the </em><em>sum </em><em>of </em><em>a </em><em>triangle</em><em> </em><em>is </em><em>1</em><em>8</em><em>0</em><em>°</em>

<em>2.We </em><em>also </em><em>know</em><em> </em><em>that </em><em>all </em><em>the </em><em>sides </em><em>of </em><em>a </em><em>triangle</em><em> </em><em>are </em><em>equal</em><em> </em><em>hence,</em><em> thier</em><em> </em><em>corresponding</em><em> </em><em>Angles </em><em>are </em><em>Equal</em><em> </em><em>too.</em>

<em>So.</em><em>.</em><em>.</em>

<em> </em><em><u>Each </u></em><em><u>angle </u></em><em><u>measures </u></em><em><u>6</u></em><em><u>0</u></em><em><u>°</u></em><em><u>. </u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>(</u></em><em><u>.</u></em><em><u>1</u></em><em><u>)</u></em>

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<em>We </em><em>can </em><em>find</em><em> the</em><em> </em><em>value</em><em> </em><em>of </em><em>x</em>

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Y_Kistochka [10]

Answer:

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Step-by-step explanation:

Hope this helped!

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