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Anon25 [30]
4 years ago
8

Divide using long division.

Formula1" title="(2x^{3} +5x^{2} -7x+6)" alt="(2x^{3} +5x^{2} -7x+6)" align="absmiddle" class="latex-formula"> ÷ (x^{2} +3x-4)
Mathematics
1 answer:
babunello [35]4 years ago
3 0

Answer:

The quotient = 2x - 1 and the remainder = 4x + 2

Step-by-step explanation:

\frac{2x^{3}+5x^{2}-7x+6}{x^{2}+3x-4}=2x+\frac{-x^{2}+x+6}{x^{2}+3x-4}

\frac{-x^{2}+x+6 }{x^{2}+3x-4}=-1+\frac{4x+2}{x^{2}+3x-4}

The quotient = 2x - 1 and the remainder = 4x + 2

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We have been given that the volume of cube is 64 cubic mm. We are asked to find the side length of the cube.

We will use volume of cube formula to solve our given problem.

V=s^3, where

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Upon substituting the given volume in above formula, we will get:

64=s^3

Now we will take cube-root on both sides of equation.

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\sqrt[3]{4^3}=\sqrt[3]{s^3}

Using rule \sqrt[n]{a^n}=a, we will get:

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