(2x + 38)° (3x – 9) What is the value of x?

Which shows 24+54 written using GCF and the distributive property

swat32

If you just want to know what is the greatest common factor of 24 and 54, it is 6. Usually, this is written as

gcf(24,54) = 6

3 0

3 years ago

Read 2 more answers

(1 pt) In a study of red/green color blindness, 950 men and 2050 women are randomly selected and tested. Among the men, 89 have

Ivahew [28]

Answer: (0.066,0.116)

Step-by-step explanation:

The confidence interval for proportion is given by :-

$p_1-p_2\pm z_{\alpha/2}\sqrt{\dfrac{p_1(1-p_1)}{n_1}+\dfrac{p_2(1-p_2)}{n_2}}$

Given : The proportion of men have red/green color blindness = $p_1=\dfrac{89}{950}\approx0.094$

The proportion of women have red/green color blindness = $p_2=\dfrac{6}{2050}\approx0.003$

Significance level : $\alpha=1-0.99=0.01$

Critical value : $z_{\alpha/2}=z_{0.005}=\pm2.576$

Now, the 99% confidence interval for the difference between the color blindness rates of men and women will be:-

$(0.094-0.003)\pm (2.576)\sqrt{\dfrac{0.094(1-0.094)}{950}+\dfrac{0.003(1-0.003)}{2050}}\approx0.091\pm 0.025\\\\=(0.09-0.025,0.09+0.025)=(0.066,\ 0.116)$

Hence, the 99% confidence interval for the difference between the color blindness rates of men and women= (0.066,0.116)

4 0

3 years ago

Answer please I will give brainiest to the one who answers first.

Lerok [7]

Answer:

$1,094,748.09
$8600.28
11 years, 10 months

Step-by-step explanation:

a) The compound interest formula can be used:

A = P(1 +r/n)^(nt)

where P is the principal invested at annual rate r compounded n times per year for t years.

A = $750,000(1 +.038/4)^(4·10) ≈ $1,094,748.09

Tamsyn's account will have a balance of $1,094,748.09 when she retires.

__

b1) The amortization formula is good for this.

A = P(r/n)/(1 -(1 +r/n)^(-nt))

where P is the amount earning interest at annual rate r compounded n times per year for t years.

A = $1,094,748.09(0.049/12)/(1 - (1 +0.049/12)^(-12·15)) ≈ $8600.28

Tamsyn can withdraw $8600.28 per month for 15 years.

__

b2) The account balance after n months will be ...

B = P(1 +r/12)^n -A((1+r/12)^n -1)/(r/12)

Filling in the known values and solving for n, we have ...

300,000 = 1,094,748.09(1.1.00408333^n) -8600.28(1.00408333^n -1)/.000408333

300,000 = 1,094,748.09(1.1.00408333^n) -2,106,191.02(1.00408333^n -1)

-1,806,191.02 = -1,011,442.93(1.00408333^n)

1.785757 = 1.00408333^n

n = log(1.785757)/log(1.00408333) = 142.3

After about 11 years 10 months, the account balance will be $300,000.

4 0

3 years ago

Evaluate 2.43+51.62+124.77

Damm [24]

2.43 + 1.62 + 124.77 = 178.82 Because all you have to do is add up all the numbers (Don't take the decimals out, leave them in) And then you get: 178.82.

Hope I helped!

- Amber

3 0

2 years ago

Evaluate the polynomial 6x - y for x= -3 and Y=2. A.15 B. -20 C.4 D.-16

ra1l [238]

I think the answer is B.
6(-3)=-18, and y=2
so 6x-y=-18-2=-20

6 0

2 years ago