If triangles AMN and ABC are similar, then
AM/AB = AN/AC
or
AM/(AM + MB) = AN/(AN + NC)
Check if this is true:
AM/AB = 21/(21 + 9) = 21/30 = 7/10
AN/AC = 14/(14 + 6) = 14/20 = 7/10
The angle at vertex A is common to both of the triangles.
Then by the side-angle-side (SAS) similarity theorem, the triangles are indeed similar.
Do 81/3=27/3=9/3=3, So you see the answer is 3^<span>4, I don't know if that's the official way to solve it but it works.</span>
1). y-3=-2(x+4)
2) slope = 3/4
y+2=3/4(x+4)
y=3/4x +1
3x-4y=4
looks like only the last one
4 3/4 - 4 1/3
= 4 9/12 - 4 4/12
= 5/12 <==== extra cup put in
(g+b)*8
first add all of the people
and then multiply that by 8
